So using a(2)=0 we can first solve for k by substituting t for 2
0 = (2-k)(2-3)(2-6)(2+3)
0 = (2-k)(-1)(-4)(5)
0 = (2-k)20
0 = 40 - 20k
-40 = -20k
k = 2
The next step would be to find all the 0s of a.
0 = (t-2)(t-3)(t-6)(t+3)
T = 2,3,6,-3
Then we find the product
2x3x6x-3 = -108
Since the problem asks for the absolute value, the answer is positive 108
Answer:
Since There Is No Equations Then The Answer Is Nothing
Explanation:
Simple
Answer:
The pressure exerted on the table due to the book is 200 N/m².
Explanation:
The pressure exerted on the table due to the book is 200 N/m².
The given parameters;
mass of the book, m = 400 g = 0.4 kg
dimension of the table, = 0.10m x 0.20 m.
gravitational field strength g = 10 N/kg.
The area of the table is calculated as follows;
A = 0.1 x 0.2 = 0.02 m²
The pressure exerted on the table due to the book is calculated as follows; where;
F is the force of the book due to its weight
Thus, the pressure exerted on the table due to the book is 200 N/m².
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