Answer:
(x−7)(x+5)=0
If any individual factor on the left side of the equation is equal to 0, the entire expression will be equal to 0.
x−7=0x+5=0
Set the first factor equal to 0 and solve.
x=7
Set the next factor equal to 0 and solve.
x=−5
The final solution is all the values that make (x−7(x+5)=0 true. x={7,−5}
38) -first you have to subtract 4-2=2
-then solve for 2^5=32
-subtract 32-20=12
-and finally multiply 12*3=36
40) -you have to solve for the numerator and denominator first
-the denominator is simple because you just have to do 2^3 which is 8
-to solve for the numerator you have to do what's in the parentheses first (3^4-7^2) which gives you 32
-the equation you should have now is 22+1^3+32 all divided by 8
-1^3 just equals 1and then you just solve for the numerator
-to solve for the numerator you have to add 22+1+32 which gives you 55 as the numerator
-since 55 cannot be divided by 8, your answer will be 55/8 or 6.875
42) -first you have to solve for the parentheses in the brackets so solve for (67-2^6) which equals to 3
-now your numerator should look like this: 2[8+(3)^3]
-you have to solve for 3^3 which is 27
-now you solve what you have left in the brackets [8+27] =35
-multiply 2*35 which gives you 70
-70 cannot be divided by 9 so your answer is 70/9 or 7.777777778
Answer:
first blank: c(x) = 45x + 14
second blank: 7
Step-by-step explanation:
explanation for second blank:
set up the equation equal to 329:
45x + 14 = 329
subtract 14 from both sides:
45x = 315
divide by 45 to leave x alone:
x = 7
Shaun will be able to rent the car for 7 days.
Answer:
C) 96%
Step-by-step explanation:
The 99% Confidence interval for the mean sale time for all homes in the neighborhood is:87.857, 112.143.
<h3>Confidence interval</h3>
a. The assumption is: Assume that the population has a normal distribution.
The CI is exact for the normal populations and for small samples the z-interval method should be used in a situation where the variable is normally distributed.
b. Confidence interval:
CI=Sample mean±z-score×Standard deviation/√Size of the sample
CI=100-2.576×20/√18, 100+2.576×20/√18
CI=100-12.143, 100+12.143
CI=87.857, 112.143
Therefore the 99% Confidence interval is 87.857, 112.143.
Learn more about Confidence interval here:brainly.com/question/15712887
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