Answer:
- The amount invested at 5%=$77,000
- The amount invested at 9%=$349,000
Step-by-step explanation:
- Let the amount invested at 5% simple interest =$x
He invested $41,000 more than 4 times the amount at 9%.
- This amount is: $(4x+41000)
Total Annual Interest Earned = $35,260
Therefore, Time=1 year
Simple Interest![=\frac{Principal X Rate X Time}{100}](https://tex.z-dn.net/?f=%3D%5Cfrac%7BPrincipal%20X%20Rate%20X%20Time%7D%7B100%7D)
Therefore, his total interest
=Interest from Investment 1 + Interest from Investment 2
![35260=\left(\frac{x*5*1}{100} \right)+\left(\frac{4x+41000*9*1}{100} \right)\\35260=0.05x+(0.36x+3690)\\35260-3690=0.05x+0.36x\\31570=0.41x\\\text{Divide both sides by 0.41}\\x=\$77000](https://tex.z-dn.net/?f=35260%3D%5Cleft%28%5Cfrac%7Bx%2A5%2A1%7D%7B100%7D%20%5Cright%29%2B%5Cleft%28%5Cfrac%7B4x%2B41000%2A9%2A1%7D%7B100%7D%20%5Cright%29%5C%5C35260%3D0.05x%2B%280.36x%2B3690%29%5C%5C35260-3690%3D0.05x%2B0.36x%5C%5C31570%3D0.41x%5C%5C%5Ctext%7BDivide%20both%20sides%20by%200.41%7D%5C%5Cx%3D%5C%2477000)
Therefore:
The amount invested at 5%=$77,000
The amount invested at 9%=$(4*77,000+41000)=$349,000
Inside a triangle, all inside angles add up to 180°
So, add the two angles:
26.4°+33.7°=60.1°
180°-60.1°=119.9°
b=119.9°
I like math because it gets me thinking a lot. math helps me in the world because we need to know how to do math in order to go shopping or we will not give the cashier the correct amount or maybe you will give them an extra amount of money because you can't do math.
Answer:
Answer is ![\frac{4}{3}](https://tex.z-dn.net/?f=%5Cfrac%7B4%7D%7B3%7D)
Step-by-step explanation:
To find the interval of x. Use our equations to equal each other.
![-x^2+2x=y,y=0](https://tex.z-dn.net/?f=-x%5E2%2B2x%3Dy%2Cy%3D0)
![-x^2+2x=0\\-x(x-2)=0\\-x=0 , (x-2)=0\\x=0 ,2](https://tex.z-dn.net/?f=-x%5E2%2B2x%3D0%5C%5C-x%28x-2%29%3D0%5C%5C-x%3D0%20%2C%20%28x-2%29%3D0%5C%5Cx%3D0%20%2C2)
![\int\limits^2_0 {-x^2+2x} \, dx](https://tex.z-dn.net/?f=%5Cint%5Climits%5E2_0%20%7B-x%5E2%2B2x%7D%20%5C%2C%20dx)
Integrate.
![\frac{-x^3}{3}+x^2\\(\frac{-2^3}{3}+2^2)-[\frac{-0^3}{3}+0^2]\\-\frac{8}{3} +4-0\\-\frac{8}{3}+\frac{12}{3} =4/3](https://tex.z-dn.net/?f=%5Cfrac%7B-x%5E3%7D%7B3%7D%2Bx%5E2%5C%5C%28%5Cfrac%7B-2%5E3%7D%7B3%7D%2B2%5E2%29-%5B%5Cfrac%7B-0%5E3%7D%7B3%7D%2B0%5E2%5D%5C%5C-%5Cfrac%7B8%7D%7B3%7D%20%2B4-0%5C%5C-%5Cfrac%7B8%7D%7B3%7D%2B%5Cfrac%7B12%7D%7B3%7D%20%20%3D4%2F3)
Using Desmos I have Graphs of both of the equations you have provided. The problem asks us to find the shaded region between those curves/equations.
Proof Check your interval of x.