Median and IQR are the most appropriate measures of center and spread for this data set.
<h3>Why are
Median and IQR the most appropriate?</h3>
Among the 3 central tendencies that includes the mean, median and mode; the median is the better measure because of the followings:
- Mean is affected by extreme values
- Mean is not correct if more outliers are present
- Mean may not represent the nature of the data whether skewed right or left.
Also, the median as the middle entry is not affected by extreme items or outliers, so the median is better than mean,
Furthermore, for the measure of spread, the IQR is better since extreme items will show higher std deviation and also some outliers mislead.
Therefore, Option B is correct.
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Answer:
<h2>B. cannot be determined</h2>
Step-by-step explanation:
For two events A and B to be independent, it means they can occur at the same time i.e the occurrence of one does not affect the other occurring. It is represented as P(A∩B) = P(A)P(B)
Given P( A) = 0.60 and P( A| B) = 0.60, to find P(B), we will use the formula for the conditional probability P( A| B) = P(A∩B) /P(B)
P( A| B) = P(A)P(B) /P(B)
P( A| B) = P(A)
Since P( A| B) = 0.60, therefore P(A) is also equal to 0.60 and P(B) cannot be determined since they cancelled out already
So it’s $15 per month so that is what you are gonna multiply by x. You start out with $75 so that’s the initial fee. 15x + 75 is your expression.
Answer:
0.4016%
Step-by-step explanation:
Estimated Value = 3,500 people , Exact attendance = 3486 people
We can see that there is a Percentage decrease . So we will apply the formula.
%Decrease = Old Value - New Value /Old Value × 100%
%decrease = 14/3486 %
%Decrease = 0.4016% (Answer)
Answer:
y = -0.2x + 1.4
Step-by-step explanation:
I graphed the points on the graph below. Then I found the slope of the line.
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