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Sergeeva-Olga [200]
3 years ago
15

Determine whether the function shown in the graph is even or odd.

Mathematics
2 answers:
erica [24]3 years ago
7 0

Answer:

Option A) The function is even because it is symmetric with respect to the y-axis.

Step-by-step explanation:

We are given a graph of the function.

We can see that the given function is symmetric around the y axis as the y axis acts as a mirror.

Symmetry around y-axis

  • The y-axis acts as the line of symmetry for the given graph.
  • A graph is said to be symmetric about the  y axis if (a,b) is on the graph, then we can find the point (-a,b) on the graph as well.

Even Function:

  • A function is said to be even if

f(x) = f(-x)

  • A function f is even if the graph of f is symmetric with respect to the y-axis

Odd function:

  • A function is said to be odd if

-f(x) = f(-x)

  • A function f is even if the graph of f is symmetric with respect to the x-axis.

Thus, we can write that the given function is an even function as the the graph is symmetric to the y-axis.

Option A) The function is even because it is symmetric with respect to the y-axis.

Murljashka [212]3 years ago
4 0

Answer:

its A

Step-by-step explanation:

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Step-by-step explanation:

The first of the two lines has a slope of -4 and a y-intercept of 19 (off the top of the graph). It will decrease 4 units for each 1 unit to the right.

The second of the two lines has a slope of +2 and a y-intercept of +1. It will increase 2 units for each 1 unit to the right.

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What is the reciprocal of -2/3
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In the air, it had an average speed of 16 1616 m/s m/sstart text, m, slash, s, end text. In the water, it had an average speed o
Diano4ka-milaya [45]

Answer:

t_a = 7 s

t_w = 5 s

Step-by-step explanation:

Given:

- The average speed in air v_a = 16 m/s

- The average speed in water v_w = 3 m/s

- The total distance D = 127 m

- The total time T = 12 s

Find:

How long did the stone fall in air and how long did it fall in the water?

Solution:

- Lets time taken by stone to drop through air as t_a = t_a.

- The time taken in water would be t_w = (12 - t_a)

- The total distance covered can be calculated as:

                            D = v_a*t_a+ v_w*(12 - t_a)

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Simplify and solve for t:

                            91 = 16*t_a - 3t_a

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                            t_a = 7 s

                            t_w = 5 s

                           

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