1. $5.76/64 Ounces
2. $1.80/15 Ounces

1. $0.09/ounce
2. $0.12/ounce

So, in conclusion, the 64 ounce bottle is cheaper than the 15 ounce bottle by $0.03.

7 0

2 years ago

PLEASE HELP 50 POINTS 100 students who are in 10th or 11th grade were asked if they participated in at least one extracurricular

Marina86 [1]

There are 2 variables in this problem. One variable is the class number and other variable is the participation in extracurricular activities. Each variable has further two categories. There are two classes: Class 10 and 11. And students either participate or do not participate in extracurricular activities, which makes 2 categories.

The best approach to solve this question is to build a table and start entering the given information in it. When the given data has been entered fill the rest on basis of the data you have.

18 students from grade 11 participate in at least one Extracurricular activities. This means the rest students i.e. 22 students from grade 11 do not participate in Extracurricular activities.

32 students from grade 10 participate in at least one Extracurricular activities. This means total students who participate in at least one Extracurricular activities are 18 + 32 = 50 students.

The rest 50 students do not participate in at least one Extracurricular activities. From these 22 are from class 11. So the rest i.e. 28 are from class 10.

5 0

3 years ago

In the figure above, what is the area of triangle QRS?

Vlad [161]

Answer:

D) 20.

Step-by-step explanation:

First find the value of x using Pythagoras theorem:

10^2 = x^2 + (2x)^2

5x^2 = 100

x^2 = 20

x = √20

= 2√5.

So the area of triangle

= 1/2 * base * height

= 1/2 * 2x * x

= x^2

= (2√5)^2

= 20.

6 0

1 year ago

What will the length of segment I' J' be?<br>

Ymorist [56]

Answer:

5.333

Step-by-step explanation:

To find the length of dilated I' J' we need to dilate the shape.

To do this you multiply each coordinate by 8/3.

Ex: (x,y) ---> (8/3x, 8/3y)

H: (0,3) ---> (8/3*0, 8/3*3)

I: (1,1) ---> (8/3*1, 8/3*1)

J: (3,1) ---> (8/3*3, 8/3*1)

K: (2,5) ---> (8/3*2, 8/3*5)

Now we plot this. (Picture attached)

The new I' coordinate: (2.667, 2.667)

The new J' coordinate: (8, 2.667)

The new length would be 8 - 2.667 so we can find the distance between the two points.

Note we are subtracting the y coordinates and not x because x coordinates represent height and y represents length

8 - 2.667 equals 5.333

So the length of segment I' J' will be 5.333

5 0

2 years ago