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2 years ago

6

1/3 x +5 =5.5 what is the value of x ?

2 answers:

Leno4ka [110]2 years ago

8 0

Answer:

x=11.5

Step-by-step explanation:

You want to isolate x. The first thing you have to do is get rid of that tricky fraction. To do this, you have to multiply the fraction by its denominator to cancel the denominator out and leaving you only with the numerator. You would also have to multiply 3 by 5.5 too. (Multiplying by the denominator only gets rid of the denominator and leaves the numerator alone. However, in your case, the numerator is one, so by getting rid of the denominator you get 1x. This can just be written as x.)

Equation would look like this:

x+5=16.5

You subtract 5 from both sides, and 16.5 minus 5 is 11.5

Equation would now look like this:

x=11.5

tester [92]2 years ago

5 0

Answer:

X= 5.5

Step-by-step explanation:

I got it right! UwU

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Andrew [12]

Given:

AD is diameter of the circle, AB is the tangent, and measure of arc ADC is 228 degrees.

To find:

The $m\angle CAB$ and $m\angle CAD$ .

Solution:

AD is diameter of the circle. So, the measure of arc AD is 180 degrees.

$m(arcADC)=m(arcAD)+m(arcDC)$

$228^\circ=180^\circ+m(arcDC)$

$228^\circ-180^\circ+=m(arcDC)$

$48^\circ+=m(arcDC)$

The measure inscribed angle is half of the corresponding subtended arc.

$m\angle CAD=\dfrac{1}{2}\times m(arcDC)$

$m\angle CAD=\dfrac{1}{2}\times 48^\circ$

$m\angle CAD=24^\circ$

AB is the tangent. So, $m\angle BAD=90^\circ$ because radius is perpendicular on the tangent and the point of tangency.

$m\angle BAD=m\angle CAB+m\angle CAD$

$90^\circ=m\angle CAB+24^\circ$

$90^\circ -24^\circ=m\angle CAB$

$66^\circ=m\angle CAB$

Therefore, $m\angle CAB=66^\circ$ and $m\angle CAD=24^\circ$ .

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