The given expression is:
![\sqrt[4]{ 9^{ \frac{1}{2}x } }](https://tex.z-dn.net/?f=%20%5Csqrt%5B4%5D%7B%209%5E%7B%20%5Cfrac%7B1%7D%7B2%7Dx%20%7D%20%7D%20%20)
4th root is equivalent to raising the expression to power
. So, re-writing the expression by converting radical to exponent:
Therefore, the given expression simplifies to 
# of bb's = (350-30*4)/22
f(x) = (230/22) = 10.45
Answer:
Step-by-step explanation:
It is true that for any given odd integer, square of that integer will also be odd.
i.e if 
is and odd integer then 
is also odd.
In the given proof the expansion for 
is incorrect.
By definition we know,
∴ 
Now, we know 
and 
will be even values
∴
will be odd
hence will be odd, which means will be odd.
Since 20 total gallons are needed, the amount of 10% solutions can be x and the amount of 20% solutions can be (20-x) since they add up to 20. In addition, the 17% solution has 20 gallons. Putting this into an equation, we get that 10% is 0.1 (by moving the decimal 2 spots to the left) , 0.2=20%, and 0.17=17%. With that information, we can determine that 10%*x+20%*(20-x)=20*0.17 due to that with 20 gallons of the 27% solution, we need a certain amount of solution. For every gallon, we add 0.17 of the solution, so we have 20*0.17. Similarly, we want that total amount to be represented by the amount of 20% + the amount of 10%.
0.1x+0.2(20-x)=0.1x+4-0.2x=-0.1x+4 using the distributive property
-0.1x+4=20*0.17=3.4. Subtract 4 from both sides to get -0.1x=-0.6, and multiply both sides by -10 (to separate x) to get x=6. Therefore, the amount of 10% solution is 6 gallons and the amount of 20% solution is 20-5=14 gallons
