Question

"At ​$1.29 million​, they closed last month for...26 percent above what they paid in​ 2007." How much did they pay in​ 2007?

Answer 1

Answer:  Amount that they paid in 2007 is 1.01 millions.

Step-by-step explanation:

Since we have given that

Number of millions paid last month = $1.29 millions

According to question, it was 26% above what they paid in 2007.

Let the amount paid in 2007 be x

So, our equation becomes,

$\frac{100+27}{100}\times x=1.29\\\\\frac{127}{100}\times x=1.29\\\\1.27\times x=1.29\\\\x=\frac{1.29}{1.27}\\\\x=1.01\ millions$

Hence, Amount that they paid in 2007 is 1.01 millions.

Answer 2

Answer:

The amount they paid in 2007 is:

                         $ 1.02381 million

Step-by-step explanation:

Let the amount paid by them in 2007 be: $ x

Now, it is given that:

"At ​$1.29 million​, they closed last month for...26 percent above what they paid in​ 2007."

i.e.

$(100+26)\%\ of\ x=1.29\\\\i.e.\\\\\dfrac{126}{100}\times x=1.29\\\\i.e.\\\\x=\dfrac{12.9\times 100}{126}\\\\i.e.\\\\x=\ \ \dfrac{129}{126}\ millon\\\\i.e.\\\\x=\ \ 1.02381\ million$