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ladessa [460]
3 years ago
15

In which container is the probability of randomly selecting a green ball on one draw 4/ 7 ?

History
1 answer:
liberstina [14]3 years ago
8 0

Answer:

The container that has 4 green balls in it out of a total of 7 balls is the right container that will prouce a probability of 4/ 7 when a ball is picked randomly on one draw

Explanation:

Probability refers to a numerical description of the likelihood of an event to take place or not to take place. It is a number whose value is between 0 and 1; 0 signifies impossibility while 1 signifies certainty

Take for example that there 7 balls in a box: we have 1 blue ball, 2 yellow balls & 4 green balls. To calculate the probability of picking one of the coloured balls on one draw is shown below

<u>Probability of picking a </u><u>white ball</u> from the box:

P = number of white ball / total number of balls

P = 0 / 7 = 0

This implies that it is impossible to pick a white ball from the box because there is no white ball in the box

<u>Probability of picking a </u><u>blue ball</u> from the box:

P = number of blue ball / total number of balls

P = 1 / 7 ≈ 0.14 or 14%

This implies that it is possible to pick a blue ball from the box. However, the likelihood of that happening is 14%

<u>Probability of picking a </u><u>yellow ball</u> from the box:

P = number of yellow ball / total number of balls

P = 2 / 7 ≈ 0.29 or 29%

This implies that it is possible to pick a yellow ball from the box. However, the likelihood of that happening is 29%

<u>Probability of picking a </u><u>green ball</u> from the box:

P = number of green ball / total number of balls

P = 4 / 7 ≈ 0.57 or 57%

This implies that it is possible to pick a green ball from the box. However, the likelihood of that happening is 57%

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