The string is assumed to be massless so the tension is the sting above the 12.0 N block has the same magnitude to the horizontal tension pulling to the right of the 20.0 N block. Thus,
1.22 a = 12.0 - T (eqn 1)
and for the 20.0 N block:
2.04 a = T - 20.0 x 0.325 (using µ(k) for the coefficient of friction)
2.04 a = T - 6.5 (eqn 2)
[eqn 1] + [eqn 2] → 3.26 a = 5.5
a = 1.69 m/s²
Subs a = 1.69 into [eqn 2] → 2.04 x 1.69 = T - 6.5
T = 9.95 N
Now want the resultant force acting on the 20.0 N block:
Resultant force acting on the 20.0 N block = 9.95 - 20.0 x 0.325 = 3.45 N
<span>Units have to be consistent ... so have to convert 75.0 cm to m: </span>
75.0 cm = 75.0 cm x [1 m / 100 cm] = 0.750 m
<span>work done on the 20.0 N block = 3.45 x 0.750 = 2.59 J</span>
Answer:
x = 24.5
Step-by-step explanation:
There are two similar triangles. In similar triangles the sides are in proportion.
Let's name big triangle as triangle 1 and small triangle as triangle 2.
The sides of the big triangle:
27 as base and the longest side (x + 7)
The sides of the small triangle:
base = 27 - 6 = 21
longest side = x
We need to find the value of x using proportion.
27/21 = (x + 7)/ x
By cross multiplying, we get
27(x) = 21(x + 7)
27x = 21x + 147
27x - 21x = 147
6x = 147
Dividing both sides by 6, we get
x = 147/6
x = 24.5
The value of x = 24.5
Hope you will understand the concept.
Thank you.
Answer:
Domain is all values of X or (-∞,∞)
Range is all the possible values of Y. Since it goes up to 3, and then it goes down, it's all values less than or equal to y, or (-∞,3] or y ≤ 3 (depending on how you need to enter the response.
Step-by-step explanation:
I don’t understand the question
If you mean
7m-4
M=8, this is the solution
7(8)-4
56-4
=52
But if you mean
7m- - 4
As in - + - = +
Then this is your answer
7(8)+4
56+4
=60
Answer:
first one with -1...21
Step-by-step explanation:
only one that follows quadratic formula format
