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Daniel [21]
4 years ago
11

Consider the statement "There are no simple solutions to life's problems."

Mathematics
1 answer:
aliya0001 [1]4 years ago
4 0

Answer:

See below

Step-by-step explanation:

Remember the notation and rules of quantifiers. ∀ is the universal quantifier and ∃ is the existential quantifier. To negate ∀x p(x) , write ∃x ¬p(x). To negate ∃x p(x) , write ∀x ¬p(x)

Part I:

A) None of life's problems have a simple solution.

B) All of life's problems have a simple solution.

C) Some of life's problems have a simple solution

D) All of life's problems have a simple solution (notice how the original statements in B and D mean exactly the same)

E) Some of life's problems do not have a simple solution.

Part II: Let x be a variable representing one of life's problems, y be a variable representing solutions, p(x):="x has a simple solution", and q(x,y):="y is a simple solution of x".

A) (∀x)(¬p(x)) or ¬(∃x)(p(x))  

B) (∀x)(∃y)(q(x,y))

C) (∃y)(∀x)(q(x,y)). Note that the order of quantifiers is important. B) and C) have different meanings. In C) there is an universal solution of all problems, in B) each problem has its solution.

D) (∀x)(p(x))

E) Same as C)

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Hello there! <br><br> Can I get someone help please ? Thanks!
natulia [17]
Since they are right triangles use Pythagorean Theorem.
a^2 + b^2 = c^2 where c is the hypotenuse.

a.  12^2 + b^2 = 13^2
144 + b^2 = 169
subtract 144 from both sides
b^2 = 25
take the square root of both sides
t = 5  This is also know as a Pythagorean Triple 5-12-13

b.  a^2 + 9^2 = 12^2
     a^2 + 81 = 144
subtract 81 from both sides
a^2 = 63
take the square root of both sides
a = √63
a = √(9 * 7)
a = 3√7

c.   6^2 + 9^2 = c^2
    36 + 81 = c^2
117 = c^2
take the square root of each side
c = √117
c = √(9*13)
x = 3√13
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Find the value of a given <img src="https://tex.z-dn.net/?f=5%5Ea%5C%5C" id="TexFormula1" title="5^a\\" alt="5^a\\" align="absmi
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Answer:

  a = 2/3

Step-by-step explanation:

A cube root is the same as a 1/3 power. The square of that gives a 2/3 power.

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<em>Additional comment</em>

You can see the relationship between a root index and an exponent if you consider what the root means.

Consider a cube root, for example. When you cube the root, you get the original number:

  (∛x)·(∛x)·(∛x) = x

Now, let's write the root as a power of x: x^a.

  (x^a)·(x^a)·(x^a) = x . . . . . where x^a = ∛x

We know this product is ...

  x^(a+a+a) = x^(3a) = x^1

This tells us that ...

  3a = 1   ⇒   a = 1/3

That is, ∛x = x^(1/3).

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