Question

-7/3x+11 i need help

Answer 1

Answer:

$\frac{33-7x}{3}$

Step-by-step explanation:

We want to simplify the algebraic expression:

$-\frac{7}{3}x+11$

We can rewrite this as:

$-\frac{7}{3}x+\frac{11}{1}$

We convert to equivalent fractions to get::

$-\frac{7}{3}x+\frac{33}{3}$

We can now add the numerators and keep one of the denominators.

$-\frac{7x+33}{3}$

We rewrite as:

$\frac{33-7x}{3}$