Answer:
3=c 4=a
Step-by-step explanation:
Answer:
Step-by-step explanation:
![\frac{a^{m}}{a^{n}}=a^{m-n}\\\\a^{m}*a^{n}=a^{m+n}\\\\\frac{125t^{-4}}{5^{-3}}*625*t^{-8}\\\\=\frac{5^{3}t^{-4}}{5^{-3}}*5^{4}*t^{-8}\\\\=5^{3-[-3]+4}*t^{-4-8}\\\\=5^{3+3+4}t^{-12}\\\\=5^{10}t^{-12}\\\\=\frac{5^{10}}{t^{12}}](https://tex.z-dn.net/?f=%5Cfrac%7Ba%5E%7Bm%7D%7D%7Ba%5E%7Bn%7D%7D%3Da%5E%7Bm-n%7D%5C%5C%5C%5Ca%5E%7Bm%7D%2Aa%5E%7Bn%7D%3Da%5E%7Bm%2Bn%7D%5C%5C%5C%5C%5Cfrac%7B125t%5E%7B-4%7D%7D%7B5%5E%7B-3%7D%7D%2A625%2At%5E%7B-8%7D%5C%5C%5C%5C%3D%5Cfrac%7B5%5E%7B3%7Dt%5E%7B-4%7D%7D%7B5%5E%7B-3%7D%7D%2A5%5E%7B4%7D%2At%5E%7B-8%7D%5C%5C%5C%5C%3D5%5E%7B3-%5B-3%5D%2B4%7D%2At%5E%7B-4-8%7D%5C%5C%5C%5C%3D5%5E%7B3%2B3%2B4%7Dt%5E%7B-12%7D%5C%5C%5C%5C%3D5%5E%7B10%7Dt%5E%7B-12%7D%5C%5C%5C%5C%3D%5Cfrac%7B5%5E%7B10%7D%7D%7Bt%5E%7B12%7D%7D)
Answer: a^8-b^8
Step-by-step explanation:
<h3>
Answer:</h3>
-5y +1
<h3>
Step-by-step explanation:</h3>
Let the polynomial to be subtracted be represented by Q. Then you want ...
... (y^2 -5y +1) -Q = y^2
... (y^2 -5y +1) = y^2 +Q . . . . add Q
... (y^2 -5y +1) -y^2 = Q . . . . .subtract y^2
... -5y +1 = Q . . . . . . . . . . . . . simplify
The polynomial to be subtracted is -5y +1.
