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3 years ago

13

I need help plz I don’t get This

1 answer:

Marysya12 [62]3 years ago

5 0

Find the area: you can split the figure into two rectangles.

The rectangles will be 7*20 and 7*11. The areas of those are <em>140 cm² and 77 cm²</em>. Add those up, and you get 217 cm².

Find the surface area: you can also split the net (the figure's surface area represented in a two-dimensional form) into two congruent triangles and three congruent rectangles. the triangles' area is <em>2(1/2*10*8) = 80 cm²</em>. The rectangles' area is <em>3(18*8) = 432 cm²</em>. Those totaled is 512 cm².

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Round 3550 to nearest 1000

ICE Princess25 [194]

3550 to the nearest 1000 would be 4000

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3 years ago

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Let f(x) = x^2 − 3x − 7. Find f(−3).

IRINA_888 [86]

Answer:

11

Step-by-step explanation:

(-3)²-3(-3)-7

9+9-7

11

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2 years ago

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Vera_Pavlovna [14]

Answer:

arc AC = 111°

Step-by-step explanation:

∠APC is a central angle, so arc AC is equal to the measure of ∠APC.

∠APC and ∠BPC are supplementary. So, m∠APC + m∠BPC = 180

m∠APC + 69 = 180

m∠APC = 111

arc AC = 111°

8 0

3 years ago

How can I find the slope to this I need help

Dmitrij [34]

Answer:

Your slope is -1

Step-by-step explanation:

Find the change in x and the change in y and put it in change in y over change in x.

Δx = -1 - -2 = 1

Δy = -1 - 0 = -1

Slope = rise over run = Change in y over change in x = Δy/Δx = -1/1

Therefore the slope is -1/1 which is written as just -1

7 0

3 years ago

Complete the steps to solve the polynomial equation x3 – 21x = –20. According to the rational root theorem, which number is a po

jeka94

Answer:

Zeroes : 1, 4 and -5.

Potential roots: $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

Step-by-step explanation:

The given equation is

$x^3-21x=-20$

It can be written as

$x^3+0x^2-21x+20=0$

Splitting the middle terms, we get

$x^3-x^2+x^2-x-20x+20=0$

$x^2(x-1)+x(x-1)-20(x-1)=0$

$(x-1)(x^2+x-20)=0$

Splitting the middle terms, we get

$(x-1)(x^2+5x-4x-20)=0$

$(x-1)(x(x+5)-4(x+5))=0$

$(x-1)(x+5)(x-4)=0$

Using zero product property, we get

$x-1=0\Rightarrow x=1$

$x-4=0\Rightarrow x=4$

$x+5=0\Rightarrow x=-5$

Therefore, the zeroes of the equation are 1, 4 and -5.

According to rational root theorem, the potential root of the polynomial are

$x=\dfrac{\text{Factor of constant}}{\text{Factor of leading coefficient}}$

Constant = 20

Factors of constant ±1, ±2, ±4, ±5, ±10, ±20.

Leading coefficient= 1

Factors of leading coefficient ±1.

Therefore, the potential root of the polynomial are $\pm 1, \pm 2, \pm 4, \pm 5, \pm 10, \pm 20$ .

3 0

4 years ago