Question

graph and show points for 3x+6yless than or equal to 12, -x+y greater than or equal to 0, x is greater than or equal to 0, y is greater than or equal to 0. Please show points and shading? Im confused bad

Answer 1

Answer:

Step-by-step explanation:

Given equations are

$3x+6y\leq 12$

$-x+y\geq 0$

Now the inequalities intersect at x=$\frac{4}{3}$

y=$\frac{4}{3}$

and we have to satisfy this also

$x\geq 0$

$y\geq 0$

Above all conditions is shown in graph

and the shaded  area is the required area

For  $3x+6y\leq 12$ put (0,0)

it satisfy the point i.e. (0,0) lie on that side which satisfy the inequality similarly check for

$-x+y\geq 0$

put (4,0) it do not satisfy the inequality therefore it lies on the side which do not satisfy the inequality