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vagabundo [1.1K]
3 years ago
14

(-1,5) (3,13) what is the equation

Mathematics
1 answer:
REY [17]3 years ago
4 0
(-1,5) = (x1,y1)
(3,13) = (x2,y2)
slope(m) = (y2-y1)/(x2-x1)
                = 2
by using slope point form
y-y1 = m (x-x1)
y-5 = 2(x+1)
2x-y+7=0
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To solve this, first make an equation:

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Answer:

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Step-by-step explanation:

To simplify this equation as much as possible, we have to get the variable y by itself.

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What is the inverse of the given relation?<br> y=3x+12
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We are asked in the problem to determine the inverse of the relation y = 3x + 12. first step is to express the equation in terms of y, that is y -12 = 3x, then exchange the places of x and y, that is x - 12 = 3y. This is the final answer
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The length of a rectangle is increasing at a rate of 4 meters per day and the width is increasing at a rate of 1 meter per day.
puteri [66]

Answer:

\displaystyle \frac{dA}{dt} = 102 \ m^2/day

General Formulas and Concepts:

<u>Pre-Algebra</u>

Order of Operations: BPEMDAS

  1. Brackets
  2. Parenthesis
  3. Exponents
  4. Multiplication
  5. Division
  6. Addition
  7. Subtraction
  • Left to Right<u> </u>

<u>Geometry</u>

Area of a Rectangle: A = lw

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  • w is width

<u>Calculus</u>

Derivatives

Derivative Notation

Implicit Differentiation

Differentiation with respect to time

Derivative Rule [Product Rule]:                                                                              \displaystyle \frac{d}{dx} [f(x)g(x)]=f'(x)g(x) + g'(x)f(x)

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle l = 10 \ meters<u />

<u />\displaystyle \frac{dl}{dt} = 4 \ m/day<u />

<u />\displaystyle w = 23 \ meters<u />

<u />\displaystyle \frac{dw}{dt} = 1 \ m/day<u />

<u />

<u>Step 2: Differentiate</u>

  1. [Area of Rectangle] Product Rule:                                                                 \displaystyle \frac{dA}{dt} = l\frac{dw}{dt} + w\frac{dl}{dt}

<u>Step 3: Solve</u>

  1. [Rate] Substitute in variables [Derivative]:                                                    \displaystyle \frac{dA}{dt} = (10 \ m)(1 \ m/day) + (23 \ m)(4 \ m/day)
  2. [Rate] Multiply:                                                                                                \displaystyle \frac{dA}{dt} = 10 \ m^2/day + 92 \ m^2/day
  3. [Rate] Add:                                                                                                      \displaystyle \frac{dA}{dt} = 102 \ m^2/day

Topic: AP Calculus AB/BC (Calculus I/II)

Unit: Implicit Differentiation

Book: College Calculus 10e

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Answer:

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