On opening the brackets;
x-3-2x+12=-5
Putting like terms together;
x-2x-3+12=-5
-x+9=-5
-x=-14
x=14
Answer:
7 in
Step-by-step explanation:
Process of elimination. It can’t be 9 or 10, because 9+9=18 and 10+10=20 (they're more than 16). 8+8=16 exactly, but there’s no room in 16 for the width. Therefore, it’s 7 because 7+7=14
Solve:-
1 quart = 4 cups
8 × 4 = 32
8 quarts = 32 cups
32, 1 cup servings.
103 adults and 183 children's attended
<em><u>Solution:</u></em>
Let "a" be the number of adults attended
Let "c" be the number of children attended
Cost of 1 adult ticket = $ 12
Cost of 1 children ticket = $ 4
At the movies, we had 286 people buy tickets
Therefore,
number of adults attended + number of children attended = 286
a + c = 286 ---- eqn 1
The total sold was $1968
Therefore,
number of adults attended x Cost of 1 adult ticket + number of children attended x Cost of 1 children ticket = 1968
![a \times 12 + c \times 4 = 1968](https://tex.z-dn.net/?f=a%20%5Ctimes%2012%20%2B%20c%20%5Ctimes%204%20%3D%201968)
12a + 4c = 1968 ------- eqn 2
<em><u>Let us solve eqn 1 and eqn 2</u></em>
From eqn 1,
a = 286 - c -- eqn 3
<em><u>Substitute eqn 3 in eqn 2</u></em>
12(286 - c) + 4c = 1968
3432 -12c + 4c = 1968
-8c = 1968 - 3432
-8c = -1464
8c = 1464
<h3>c = 183</h3>
<em><u>Substitute c = 183 in eqn 3</u></em>
a = 286 - 183
<h3>a = 103</h3>
Thus 103 adults and 183 children's attended
c = 5j
c + j = 18
5j + j = 18
6j = 18
j = 3
c = 5(3) = 15
Answer: Carole is 15, Joe is 3