The answer would be
C. succession
I am not 100% sure, though
Answer:
A person can select 3 coins from a box containing 6 different coins in 120 different ways.
Step-by-step explanation:
Total choices = n = 6
no. of selections to be made = r = 3
The order of selection of coins matter so we will use permutation here.
Using the formula of Permutation:
nPr = 
We can find all possible ways arranging 'r' number of objects from a given 'n' number of choices.
Order of coin is important means that if we select 3 coins in these two orders:
--> nickel - dime - quarter
--> dime - quarter - nickel
They will count as two different cases.
Calculating the no. of ways 3 coins can be selected from 6 coins.
nPr =
= 
nPr = 120
-x+y=3
y=x+3
2x + x + 3 =6
3x + 3 = 6
3x = 3
x = 1
-1 + y = 3
y = 4
2(1) + y = 6
2 + y = 6
y = 4
Solution: (1, 4)
Answer:
choice C: x2 -3x -3
Step-by-step explanation:
(3x^2-7x+2)-(2x^2-4x+5)
becomes
3x^2-7x+2 -2x^2+4x-5
adding
3x^2-2x^2 -7x+4x +2-5
which is
x^2 -3x -3
The answer for this is 22.325