- Yes, this linear equation is correct on point (0,-2).
Given that:
x - 5y = 10;
(0, -2)
To find
- We have to prove LHS = RHS
So, according to the question
We have,
The linear equation,
x - 5y = 10; and point is (0,-2)
From equation,
x - 5y = 10
Take the left part of given linear equation,
LHS = x - 5y
Now, putting the values, x = 0 and y = -2.
Then, we will be get.
= x - 5y
= (0) - 5 ×(-2)
= - 5 × -2
= 10.
So, we can say that
LHS = RHS.
Where,
LHS = Left Hand Side.
RHS = Right Hand Side.
We can solve that linear equation in other way,
When we put x = 0, we get y = -2.
So, if we put x = 1, we get y = -9/5.
Similarly, if x = 2, then y = -8/5.
Now, we can say that points (0,-2), (1,-9/5) and (2,-8/5) are lie in the linear equation x - 5y = 10.
To learn more about linear equation, please click on the link;
brainly.com/question/13738061
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