Answer:
V ≈471.24 mm^3
Step-by-step explanation:
The formula for cylinder volume is πr^2 x h, so ((π x 25) x h). That's just 25π x 6. That is about 471.238898, which rounded is almost 471.24. Or, in terms of π, you could leave your answer as 150π mm^3
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Answer:
Step-by-step explanation:
Solutions, zeros, and roots of a polynomial are all the same exact thing and can be used interchangeably. When you factor a polynomial, you solve for x which are the solutions of the polynomial. Since, when you factor a polynomial, you do so by setting the polynomial equal to 0, by definition of x-intercept, you are finding the zeros (don't forget that x-intercepts exist where y is equal to 0). There's the correlation between zeros and solutions.
Since factoring and distributing "undo" each other (or are opposites), if you factor to find the zeros, you can distribute them back out to get back to the polynomial you started with. Each zero or solution is the x value when y = 0. For example, if a solution to a polynomial is x = 3, since that is a zero of the polynomial, we can set that statement equal to 0: x - 3 = 0. What we have then is a binomial factor of the polynomial in the form (x - 3). These binomial factors found from the solutions/zeros of the polynomial FOIL out to give you back the polynomial equation.
Answer:
[C] 25π square inches
Step-by-step explanation:
<u><em>Given that:</em></u>
<em>the long hand of the clock is about 5 inches long.</em>
<u><em>To Find:</em></u>
<em>What is the approximate area of the clock face?</em>
<u><em>Solve:</em></u>
<em>Formula - </em><em>A =πr²</em>
<em>Note that;</em>
<em>π = 3.14 (about)</em>
<em>Radius - 5 inches</em>
<em>A =πr²</em>
<em>A = 3.14(5)²</em>
<em>A = 3.14(25)</em>
<em>A = 78.5</em>
<em>Now let see the answer choices:</em>
<em>A. 5π square inches ≈ 5(3.14) = 15.7</em>
<em>B. 10 π square inches ≈ 10(3.14) = 31.4</em>
<em>C. 25 π square inches ≈ 25(3.14) = 78.5</em>
<em>D. 100 π square inches ≈ 100(3.14) = 314</em>
<em />
<em>Hence, the answer is [C] 25 π square inches </em>
<em />
<u><em>Kavinsky~</em></u>
