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dexar [7]
3 years ago
7

What does -8(4+9x)=7(-2-11x) equal

Mathematics
1 answer:
hjlf3 years ago
3 0

Answer:

x=18/5

Step-by-step explanation:

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Helpp the topic is about limits
erik [133]

Since we want to find the value of <em>k</em><em> </em>where the limit exists, set both equations equal to each other. Then substitute <em>x</em> = -1 in for each equation to find <em>k</em><em>.</em>

<em>kx - 3 =  {x}^{2}  + k</em>

1. Set both equations equal.

- k -  3 = 1 + k

2. Substitute <em>x</em><em> </em>= -1.

- 3 = 1 + 2k

3. Solve for <em>k</em><em> </em>by adding <em>k</em><em> </em>to both sides. Continue the process of solving the equation.

- 4 = 2k

k =  - 2

Thus, <em>k</em><em> </em>= -2. Check by graphing the function.

8 0
3 years ago
I need help trying to do this
GREYUIT [131]

Answer:

me likey points ❤️❤️❤️

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3 years ago
Simplify the expression: 1/1+cot^2x
Art [367]

When you simplify the expression 1/1+cot^2x the final product is C. sin^2 (x).

Hope this helps!

8 0
3 years ago
There are 250 tables total in a cafeteria. There are 150 tables with red tablecloths and 100 tables with white tablecloths. As p
dimaraw [331]

Answer:

60%

Step-by-step explanation:

If there are 250 tables you can multiply it by 4 to work with 1000. This means you have to multiply the other table cloth numbers. 150 x 4 = 600. 100 x 4 = 400. Once you simplify you can get 40 white and 60 red out of 100.  60/100 = 60%.

7 0
3 years ago
What is the difference? StartFraction 2 x + 5 Over x squared minus 3 x EndFraction minus StartFraction 3 x + 5 Over x cubed minu
inn [45]

Answer:

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Step-by-step explanation:

The given expression is

\frac{2x+5}{x^{2} -3x} -\frac{3x+5}{x^{3} -9x} -\frac{x+1}{x^{2}-9}

First, we need to factor each denominator

\frac{2x+5}{x(x-3)} -\frac{3x+5}{x(x+3)(x-3)} -\frac{x+1}{(x-3)(x+3)}

So, the least common factor (LCF) is x(x-3)(x+3), because they are the factors that repeats.

Now, we diviide the LCF by each denominator, to then multiply it by each numerator.

\frac{(x+3)(2x+5)-3x-5-x(x+1)}{x(x-3)(x+3)} =\frac{2x^{2}+5x+6x+15-3x-5-x^{2}-x }{x(x-3)(x+3)}\\\frac{x^{2}+7x+10}{x(x-3)(x+3)}

Then, we factor the numerator, to do so, we need to find two numbers which product is 10 and which sum is 7.

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

Therefore, the expression is equivalent to

\frac{(x+5)(x+2)}{x(x-3)(x+3)}

8 0
3 years ago
Read 2 more answers
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