Answer:
3 has to be 3
Step-by-step explanation:
n neg so 3
Answer:
The unit price at Price-Club is $0.2158 per ounce.
The unit price at Shop Mart is $0.2925 per ounce.
Step-by-step explanation:
Price Club:
12-ounce box of crackers for $2.59
So
12 ounces - $2.59
1 ounce - x



The unit price at Price-Club is $0.2158 per ounce.
Shop Mart:
1-pound box of crackers for $4.68.
1 pound is 16 ounces. So
16 ounces - $4.68
1 ounce - x



The unit price at Shop Mart is $0.2925 per ounce.
Answer:
A two-sample t-test for a difference between sample means
Step-by-step explanation:
<u>Explanation</u>:-
A random sample of 50 bags from each of Brand X and Brand Y was selected
Given two sample sizes n₁ and n₂
Each bag was held from its rim, and one-ounce weights were dropped into the bag one at a time from the same height until the bag ripped
mean of ounces the first sample = x⁻
mean of the second sample =y⁻
Given data one-ounce weights were dropped into the bag one at a time from the same height until the bag ripped
Standard deviation of the first sample = S₁
Standard deviation of the second sample = S₂
Now we use t - distribution for a difference between the means

where

Degrees of freedom γ = n₁ +n₂ -2
Answer:
Maximum revenue = $8000
The price that will guarantee the maximum revenue is $40
Step-by-step explanation:
Given that:
Price of product = $35
Total sale of items = 225
For every dollar increase in the price, the number of items sold will decrease by 5.
The total cost of item sold = 225 ×35
The total cost of item sold = 7875
If c should be the dollar unit in price increment;
Therefore; the cost function is : ![[35+c(1)][225-5(c)]](https://tex.z-dn.net/?f=%5B35%2Bc%281%29%5D%5B225-5%28c%29%5D)
For maximum revenue;

![\dfrac{d}{dc}[[35+c(1)][225-5(c)]]=0](https://tex.z-dn.net/?f=%5Cdfrac%7Bd%7D%7Bdc%7D%5B%5B35%2Bc%281%29%5D%5B225-5%28c%29%5D%5D%3D0)
0+225-35× 5 -10c = 0
225 - 175 =10c
50 = 10c
c = 50/10
c = 5
Maximum revenue = ![[35+c(1)][225-5(c)]](https://tex.z-dn.net/?f=%5B35%2Bc%281%29%5D%5B225-5%28c%29%5D)
Maximum revenue = ![[35+5(1)][225-5(5)]](https://tex.z-dn.net/?f=%5B35%2B5%281%29%5D%5B225-5%285%29%5D)
Maximum revenue = (35 + 5)(225-25)
Maximum revenue = (40 )(200)
Maximum revenue = $8000
The price that will guarantee the maximum revenue is :
=(35 +c)
= 35 + 5
= $40