3 years ago

Insert four arithmetic means between 15 and 45

Mathematics

1 answer:

seraphim [82]3 years ago

4 0

Answer:

book ma Hoga okay it this very easy question

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3 years ago

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PLEASEEE Find the angles

4vir4ik [10]

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Step-by-step explanation:

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Suppose scores on exams in statistics are normally distributed with an unknown population mean and a population standard deviati

Anna71 [15]

Answer:

( 67.18, 68.82)

Step-by-step explanation:

Let $\mu$ be the true (population) mean of statistics exam scores. We have a large random sample of n = 36 scores with a sample mean (sample mean score) of $\bar{x} = 68$ . We know that the population standard deviation is $\sigma = 3$ . A pivotal quantity is $(\bar{x}-\mu)/(3/\sqrt{36}) = (\bar{x}-\mu)/(3/6) = (68-\mu)/(1/2)$ which is approximately normally distributed and $P(-z_{0.05}\leq(68-\mu)/(1/2)\leq z_{0.05}) = 0.90$ where $-z_{0.05} =-1.6449$ , and so, $P(-1.6449\leq(68-\mu)/(1/2)\leq 1.6449) = 0.90$ . Therefore the 90% confidence interval is (68-(1/2)(1.6449), 68+(1/2)(1.6449)), i.e., ( 67.18, 68.82)