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4 years ago

Solve (12^5)^3 = 12_____?

1 answer:

7 0

<span>1.5407022e+16 im pretty sure is the answer. i did use a little help but i still pretty sure this is the answer.</span>

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I don't know how to do these sort of problems... Can someone help me out?

VLD [36.1K]

180=76+4x
180-76=4x
104=4x
104/4=x
26=x
Measurement A= 26

6 0

3 years ago

Michael has a pail that holds 5 gallons of

damaskus [11]

Answer:

20 quarts.

Step-by-step explanation:

Because there are 20 quarts in 5 gallons.

5 0

3 years ago

write all possible odd 5 digit number using the digits 1, 4, 7, 8 and 0 with the digit 1 in 10000 place?

KiRa [710]

1,4087
10,847
18047
18887
17777
14447
10007
11117

3 0

3 years ago

What is the modulus and argument after (StartRoot 3 EndRoot) (cosine (StartFraction pi Over 18 EndFraction) + I sine (StartFract

fgiga [73]

Answer:

$|z| = 27$ -- Modulus

$\theta = \frac{\pi}{3}$ --- Argument

Step-by-step explanation:

Given

$((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6$

Required

Determine the modulus and the argument

We have that:

$z = ((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6$

Expand:

$z = (\sqrt 3)^6(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$

$z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$

A complex equation can be expressed as:

$z = |z| e^{i\theta}$

Where

$|z| = modulus$

$\theta = argument$

Where

$e^{i\theta} = (cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})$

So:

$z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6$ becomes

$z = 27(e^{i\frac{\pi}{18}})^6$

By comparison:

$e^{i\theta} = (e^{i\frac{\pi}{18}})^6$

This gives:

${i\theta} = i\frac{\pi}{18}}*6$

${i\theta} = i\frac{6\pi}{18}}$

${i\theta} = i\frac{\pi}{3}}$

Divide through by i

$\theta = \frac{\pi}{3}$

Hence, the modulus, z is:

$|z| = 27$

And the argument $\theta$ is

$\theta = \frac{\pi}{3}$

4 0

3 years ago

What is the slope of the line that passes through the points (10, 6) and (9,5)

VMariaS [17]

Answer:

Step-by-step explanation:

m=(y2-y1)/(x2-x1)

m=(5-6)/(9-10)

m=-1/-1

m=1

3 0

3 years ago