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masya89 [10]
4 years ago
11

Solve (12^5)^3 = 12_____?

Mathematics
1 answer:
nydimaria [60]4 years ago
7 0
<span>1.5407022e+16 im pretty sure is the answer. i did use a little help but i still pretty sure this is the answer.</span>
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I don't know how to do these sort of problems... Can someone help me out?
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3 years ago
Michael has a pail that holds 5 gallons of
damaskus [11]

Answer:

20 quarts.

Step-by-step explanation:

Because there are 20 quarts in 5 gallons.

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3 years ago
write all possible odd 5 digit number using the digits 1, 4, 7, 8 and 0 with the digit 1 in 10000 place?
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3 years ago
What is the modulus and argument after (StartRoot 3 EndRoot) (cosine (StartFraction pi Over 18 EndFraction) + I sine (StartFract
fgiga [73]

Answer:

|z| = 27 -- Modulus

\theta = \frac{\pi}{3} --- Argument

Step-by-step explanation:

Given

((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6

Required

Determine the modulus and the argument

We have that:

z = ((\sqrt 3)(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18}))^6

Expand:

z = (\sqrt 3)^6(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6

z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6

A complex equation can be expressed as:

z = |z| e^{i\theta}

Where

|z| = modulus

\theta = argument

Where

e^{i\theta} = (cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})

So:

z = 27(cos\frac{\pi}{18} + i\ sin\frac{\pi}{18})^6 becomes

z = 27(e^{i\frac{\pi}{18}})^6

By comparison:

e^{i\theta} = (e^{i\frac{\pi}{18}})^6

This gives:

{i\theta} = i\frac{\pi}{18}}*6

{i\theta} = i\frac{6\pi}{18}}

{i\theta} = i\frac{\pi}{3}}

Divide through by i

\theta = \frac{\pi}{3}

Hence, the modulus, z is:

|z| = 27

And the argument \theta is

\theta = \frac{\pi}{3}

4 0
3 years ago
What is the slope of the line that passes through the points (10, 6) and (9,5)
VMariaS [17]

Answer:

1

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m=(y2-y1)/(x2-x1)

m=(5-6)/(9-10)

m=-1/-1

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3 years ago
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