Question

Recall that 0°C = 32°F and 100°C =212°F

Answer 1

(0,32)(100,212)
slope = (y2 - y1) / (x2 - x1)
slope(m) = (212 - 32) / (100 - 0) = 180/100 = 9/5 (or 1.8)
so the slope of the line is 9/5...this means that a farenheit degree change is equivalent to a celsius change of 9/5(or 1.8 degrees)

now we find the y int.
y = mx + b
slope(m) = 9/5
(0,32)..x = 0 and y = 32
now we sub and find b, the y int
32 = 9/5(0) + b
32 = b
so ur y int is 32...this means that when celsius temp starts at 0, farenheit temp is 32 degrees