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bekas [8.4K]
3 years ago
11

What are some multiplication factors for 12

Mathematics
2 answers:
frosja888 [35]3 years ago
6 0
Hi

Here are some examples:

1. 12
2.24
3.36
4.48
5.60
6. 72
7.84
8.96
coldgirl [10]3 years ago
4 0
12,24,36,48,60 all of that sort
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4a + 3 - 9 = -7 + 2 + a
rjkz [21]
4a + 3 - 9 = -7 + 2 + a
4a - 6 = -5 + a
4a - a = -5 + 6
3a = 1 / : 3
a = 1/3

6 0
4 years ago
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Yellow Cab Taxi charges a $1.75 flat rate in addition to $.55 per mile. Katie has no more than $10 to spend on a ride. How many
katrin2010 [14]
Take $1.75 from the $10 then dived the 55cents into the sum. Thus $10 - $1.75 = $8.25. / .55 =15 miles exactly
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3 years ago
How many solutions are there to this system of equations?
Zinaida [17]

Answer:

one

Step-by-step explanation:

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4 years ago
A chemist examines 12 sedimentary samples for bromide concentraction. The mean bromide concentration for the sample date is 0.43
Umnica [9.8K]

Answer:

a) z = 1.645

b) Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

Step-by-step explanation:

Population is approximately normal, so we can find the normal confidence interval.

We have that to find our \alpha level, that is the subtraction of 1 by the confidence interval divided by 2. So:

\alpha = \frac{1-0.9}{2} = 0.05

Now, we have to find z in the Ztable as such z has a pvalue of 1-\alpha.

So it is z with a pvalue of 1-0.05 = 0.95, so z = 1.645. This is the critical value, the answer for a).

Now, find M as such

M = z*\frac{\sigma}{\sqrt{n}}

In which \sigma is the standard deviation of the population and n is the size of the sample.

M = 1.645*\frac{0.0325}{\sqrt{12}} = 0.015

The lower end of the interval is the sample mean subtracted by M. So it is 0.437 - 0.015 = 0.422cc/m³.

The upper end of the interval is the sample mean added to M. So it is 0.437 + 0.015 = 0.452 cc/m³.

b)

Lower endpoint: 0.422cc/m³

Upper endpoint: 0.452 cc/m³

4 0
3 years ago
Write an expression to represent the side length of a square in terms of the square's perimeter,
Likurg_2 [28]

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3 0
3 years ago
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