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3 years ago

Solve for b. b 0.6=−1 what is the answer?

Mathematics

2 answers:

mr Goodwill [35]3 years ago

5 0

Answer:

value of b is, -1.6

Step-by-step explanation:

Given the equation:

$b+0.6=1$

Subtraction property of equality states that you subtract the same number to both sides of an equation.

Subtract 0.6 to both sides of an equation [1]

$b+0.6-0.6 = -1-0.6$

Simplify:

$b = -1-0.6$

⇒ $b =-1.6$

Therefore, the value of b is, -1.6

Sati [7]3 years ago

3 0

I assume the expression is written this way,
b(0.6) = -1
or this can be better written as,
0.6b = -1
To answer the question, we divide both sides of the equation by 0.6 and that will give us an answer of,
b = -1/0.6 = -5/3

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Form an identity using -5x+9=9_

koban [17]

Answer:

-5x+9=9

-5x+9-9=9-9

-5x=0

x= 0/5

x= 0

Step-by-step explanation:

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4 years ago

Plz answer i will mark as brainliest follow u and give you thx..but in return i need full proper answer

Lynna [10]

Answer:

Explanation:

There are 36 possible outcome:
(1,1) (1,2) (1,3)...(1,6)
(2,1)....(2,6)
(3,1).....(3,6)
(4,1)....(4,6)
(5,1)....(5,6)
(6,1).....(6,6)

The possibility of getting a doublet are 6 possible outcome:

(1,1) (2,2) (3,3) (4,4) (5,5) (6,6)

P = 6/36 = 1/6

The possibility for getting a sum of prime number are 8 outcome:
(1,2) (2,1) (2,3) (3,2) (5,2) (2,5) (5,6) (6,5)

P = 8/36 = 2/9

3 0

3 years ago

Coach Burns charted the change in his runnersâ€™ 5K times from the first race of the year to the second race of the year. Which

Tom [10]

Yasim is Albert who ran the race at a time that was 15.7 seconds shorter, So, Yasim is the student who improved the most by decreasing the time needed to run the race.

<h2>Given that,</h2>

Coach Burns charted the change in his runners' 5K times from the first race of the year to the second race of the year.

Which student improved the most by decreasing the time needed to run the race?

<h3>According to the question,</h3>

Coach Burns charted the change in his runners' 5K times from the first race of the year to the second race of the year.

In the given option Yasim has the lowest value of the time which is -37.5 seconds.

Yasim was the most improved student because Yasim ran the second race in a time that was 37.4 seconds shorter than the first race.

Following Yasim is Albert who ran the race at a time that was 15.7 seconds shorter.

At the third place in improvement is Cody who actually was worse off than the first race along with the 4th place Hannah.

Hence, Yasim students improved the most by decreasing the time needed to run the race.

For more details about the Equation refer to the link given below.

brainly.com/question/3842749

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2 years ago

Which graph does not represent a function?

AleksandrR [38]

Answer: B

Step-by-step explanation:

It is.

8 0

3 years ago

Read 2 more answers

A very large batch of parts (assume a normal distrbution0 from a manufacturer has a mean weight = 43g and a standard deviation =

AVprozaik [17]

Answer:

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

Step-by-step explanation:

To solve this question, we need to understand the normal probability distribution and the central limit theorem.

Normal probability distribution:

Problems of normally distributed samples are solved using the z-score formula.

In a set with mean $\mu$ and standard deviation $\sigma$ , the zscore of a measure X is given by:

$Z = \frac{X - \mu}{\sigma}$

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

Binomial probability distribution:

The binomial probability is the probability of exactly x successes on n repeated trials, and X can only have two outcomes.

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

In which $C_{n,x}$ is the number of different combinations of x objects from a set of n elements, given by the following formula.

$C_{n,x} = \frac{n!}{x!(n-x)!}$

And p is the probability of X happening.

Percentage of parts with weights exceeding 45g?

1 subtracted by the pvalue of Z when X = 45. So

We have $\mu = 43, \sigma = 4$

$Z = \frac{X - \mu}{\sigma}$

$Z = \frac{45 - 43}{4}$

$Z = 0.5$

$Z = 0.5$ has a pvalue of 0.6915

1 - 0.6915 = 0.3075

If you slect 16 parts at random form that batch, what is the probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g?

This is P(X = 8) when n = 16, p = 0.3075. So

$P(X = x) = C_{n,x}.p^{x}.(1-p)^{n-x}$

$P(X = 8) = C_{16,8}.(0.3075)^{8}.(0.6915)^{8} = 0.0544$

5.44% probability that exactly 8 of the 16 parts you selected will have weights exceeding 45g

4 0

3 years ago