All categories

3 years ago

Can someone help me please and thank you

Mathematics

1 answer:

topjm [15]3 years ago

6 0

The answer is 18.

Here's how I got my answer:

Step 1: Subtract $7-4$ to get 3. Which will leave you with $2 * 3^4 /9$

Step 2: Solve $3^4$ (81). Which leaves you with $2 * 81/9$

Step 3: Do $2 * 81/9$ to get $162/9$

Step 4: Simplify $162/9$ to get your answer: 18

You might be interested in

A distribution has a mean of 90 and a standard deviation of 15. Samples of size 25 are drawn randomly from the population. Find

raketka [301]

Answer:

The probability is 0.04746

Step-by-step explanation:

Firstly, we calculate the z-score here

Mathematically;

z-score = x-mean/SD/√n

Where from the question;

x = 85, mean = 90 , SD = 15 and n = 25

Plugging these values into the equation, we have;

Z = (85-90)/15/√25 = -5/15/5 = -1.67

So the probability we want to calculate is ;

P(z > -1.67)

We use the standard normal distribution table for this;

P(z > -1.67) = 0.04746

4 0

3 years ago

Ill mark brainliest, question is attached

irga5000 [103]

Answer:

The answer is 6.

3 0

3 years ago

Read 2 more answers

How to have a different rectangle with the same perimeter

Nuetrik [128]

To have a different rectangle with the same perimeter you just have different measurements. If you need an example let me know!

7 0

3 years ago

Whats the answer for number 3

Karolina [17]

cant see the full question ;/

5 0

3 years ago

Use the following table for questions 11-13.A baseball manager believes a linear relationship exists between the number of Home

slamgirl [31]

The regression equation of Y on X is given by the following formula:

$Y-\bar{Y}=b_{yx}(X-\bar{X})$

Where byx is given by the formula:

$b_{yx}=\frac{N\sum^{}_{}XY-\sum^{}_{}X\sum^{}_{}Y}{N\sum^{}_{}X^2-(\sum^{}_{}X)^2}$

Where N is the number of values (N=8). We need to find the sum of X values, the sum of Y values, the average of X, the average of Y, the sum of X*Y and the sum of X^2.

The table of values is:

The values we need to know are on the following table:

By replacing the known values in the formula we obtain:

$\begin{gathered} b_{yx}=\frac{8\cdot26125-167\cdot995}{8\cdot4649-(167)^2} \\ b_{yx}=\frac{209000-166165}{37192-27889} \\ b_{yx}=\frac{42835}{9303} \\ b_{yx}=4.6 \end{gathered}$

Now, the average of X and Y is the sum divided by N, then:

$\begin{gathered} \bar{X}=\frac{167}{8}=20.87 \\ \bar{Y}=\frac{995}{8}=124.37 \end{gathered}$

Replace these values in the formula and find the regression equation as follows:

$\begin{gathered} Y-124.37=4.6(X-20.87) \\ Y-124.37=4.6X-4.6\cdot20.87 \\ Y=4.6X-96.11+124.37 \\ Y=4.6X+28.26 \end{gathered}$

The answer is a) y=4.6x+28.26

7 0

1 year ago