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Softa [21]
2 years ago
7

A graph titled Marginal Cost of Bikes has the bike number of the x-axis, from 1 to 7, and marginal cost on the y-axis, from 0 to

70 dollars in increments of 10. Bike 1 is 30 dollars, bike 2 is 18 dollars, bike 3 is 12 dollars, bike 4 is 20 dollars, bike 5 is 30 dollars, bike 6 is 50 dollars, and bike 7 is 60 dollars. This graph shows the marginal cost of producing each bike. Select the correct answer from the options available. Based on this graph, which bike has a marginal cost of $20? Bike 1 Bike 2 Bike 3 Bike 4
Mathematics
1 answer:
aleksklad [387]2 years ago
4 0

Answer:

80

20

50

60

Step-by-step explanation:

subtract the total cost form the bike above the bike in question and thats ur answer

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Step-by-step explanation:

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3 years ago
There are 48 cards in a pack and each card is either red or black.
Anon25 [30]

Answer:

Step-by-step explanation:

Red:black = 1:1

Red cards = x

Black cards =x

x + x = 48

2x = 48

x = 48/2

x = 24

No. of red cards = 24

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Now 8 red cards are removed

So, No. of red cards = 24 - 8 =16

Red: Black = 16:24

=\frac{16}{24}=\frac{2}{3}

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2 years ago
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3 years ago
a cashier at the supermarket has $685 in 4 different denomination bills in her register at the end of the day. the number of $5
netineya [11]

9514 1404 393

Answer:

  • 85 ones
  • 70 fives
  • 15 tens
  • 2 fifties

Step-by-step explanation:

Let a, b, c, d represent the numbers of $1, $5, $10, and $50 bills, respectively. The problem statement tells us ...

  a +5b +10c +50d = 685 . . . . . total amount of cash

  b = 10 +4c . . . . . . . . . . . . the number of fives is 10 more than 4 times tens

  a = b+c . . . . . . . . . . . as many ones as fives and tens combined

  d = 2 . . . . . . . . . . the register contained 2 fifty-dollar bills

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Substituting for 'a', then for 'b', we have ...

  (b+c) +5b +10c +50d = 685

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Substituting d=2 and subtracting 160 gives ...

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  b = 10 +4c = 10 +4(15) = 70

  a = b+c = 70 +15 = 85

The register contained ...

  • 85 ones
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  • 15 tens
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5 0
2 years ago
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1st way- 3^2 * 3^3
2nd way- 3 * 3^4
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