Question

What is the solution of StartRoot x squared + 49 EndRoot = x + 5?

Answer 1

$x=\frac{12}{5}$ or x= twelve-fifths

Option A is correct.

Step-by-step explanation:

We need to find the solution of:

$\sqrt{x^2+49}=x+5$

Solving:

Taking square on both sides:

$(\sqrt{x^2+49})^2=(x+5)^2\\x^2+49=x^2+2(x)(5)+25\\Simplifying:\\x^2+49-x^2-10x-25=0\\-10x+24=0\\-10x=-24\\x=\frac{-24}{-10}\\ x=\frac{24}{10}\\x=\frac{12}{5}$

Verifying the solution by putting x = 12/5 in the given equation, we get true result.

So, $x=\frac{12}{5}$ or x= twelve-fifths

Option A is correct.

Keywords: Solving Square root Equations

Learn more about Solving Square root Equations at:

• brainly.com/question/4034547
• brainly.com/question/1716201
• brainly.com/question/10666510

#learnwithBrainly

Answer 2

Answer:

option A is correct, just took the test.

Step-by-step explanation: