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Nat2105 [25]
3 years ago
9

Which equation is related to (squ)x+10)-1?

Mathematics
2 answers:
mihalych1998 [28]3 years ago
8 0

  (x + 10)² - 1

= (x² + 20x + 100) - 1

= x² + 20x + 99

None of the choices you provided are correct. Did you type in the question wrong?

Ulleksa [173]3 years ago
7 0

Answer:

<h2>None of the above.</h2>

Step-by-step explanation:

The given expression is

(x+10)^{2}-1

To solve this expression, we first need to solver the power of the binomial with the following formula

(a+b)^{2}=a^{2}+2ab+b^{2}

Where a=x and b=10, so

(x+10)^{2}-1=x^{2} +2(x)(10)+10^{2}-1=x^{2}  +20x+100-1\\x^{2} +20x+99=0

So, we need to find which option is equal to the expression we found.

However, neither of the choices are equivalent to the expression we found.

Therefore, the answer is none of the above.

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Answer

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the median number is 1

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Find 3 consecutive numbers that equal 45
tatyana61 [14]

Answer:

14,15,16

Step-by-step explanation:

Let x be the first number

Consecutive means in a row

x+1 is the second number

x+2 is the third number

x+ x+1 + x+2 = 45

Combine like terms

3x+3 = 45

Subtract 3 from each side

3x+3-3=45-3

3x = 42

Divide each side by 3

3x/3 = 42/3

x =14

The first number is 14

The second number is  14+1 = 15

The third number is 14+2 =16

7 0
3 years ago
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If Amy gross income was 2500 but her net income was only 2350 how much did Amy pay in taxes?
pashok25 [27]

Answer:

150

Step-by-step explanation:

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3 0
3 years ago
Anybody help me to solve this question. ​
Mumz [18]

Answer:

\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are\ in\ AP

Step-by-step explanation:

Given that (b-c)^2, (c-a)^2 , (a-b)^2 are in AP

To prove: \dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)} are in AP

From given as we know if p , q, r are in AP then 2q= p+r.

2(c-a)^2= (b-c)^2+(a-b)^2\\\\\Rightarrow 2(c^2+a^2-2ac)=b^2+c^2-2bc+a^2+b^2-2ab\\\\\Rightarrow 2c^2+2a^2-4ac= 2b^2+c^2+a^2 -2bc-2ab\\\\\Rightarrow a^2+c^2-2b^2-4ac= -2bc-2ab\\\\\Rightarrow a^2-2b^2+c^2= 4ac-2bc-2ab

Now

\dfrac{1}{(b-c)},\dfrac{1}{(c-a)} ,\dfrac{1}{(a-b)}2\dfrac{1}{(c-a)} =\dfrac{1}{(b-c)}+\dfrac{1}{(a-b)}\\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-b+b-c}{(b-c)(a-b)} \\\\\Rightarrow \dfrac{2}{(c-a)}= \dfrac{a-c}{(b-c)(a-b)} \\\\\Rightarrow2(b-c)(a-b) = (c-a)(a-c) \\\\\Rightarrow 2(ab-b^2-ac+bc)= -(a-c)^2\\\\\Rightarrow 2ab- 2b^2-2ac+2bc = -a^2-c^2+2ac\\\\\Rightarrow a^2-2b^2+c^2=4ac-2ab-2bc

Which is the result of AP

.

Hence proved

6 0
3 years ago
On the last chemistry exams a student scored 83, 89, and 92. What score must the student earn on the next exam to have an averag
Dmitrij [34]

In order to get an average of 90, the student needs to get a score of 96.

The average can be found by summing up all the numbers in a data set and then dividing it by the number of characters in that dataset.

Assuming the average is 90, and that the score the student needs to get is x, the formula would be:

<em>Average = Sum of scores / Number of scores </em>

90 = (83 + 89 + 92 + x) / 4

90 x 4 = 264 + x

x = 360 - 264

x = 96

The student needs to get a score of 96 on the last exam.

<em>Find out more at brainly.com/question/13406591.</em>

5 0
2 years ago
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