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blagie [28]
3 years ago
11

What is the simplified form of x2 • y–3 • x4

Mathematics
2 answers:
Alex787 [66]3 years ago
3 0
<span>x^2 • y^–3 • x^4
= x^6 / y^3</span>
Nana76 [90]3 years ago
3 0
It is simplified to X6 × y-3
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For function of g,g(0)=1 and g(1)=5 assuming g is a linear function what is g(3)<br>​
lawyer [7]

Answer:

g(3) = 13

Step-by-step explanation:

Given

g(0) = 1

g(1) = 5

Required

Find g(3)

Since g(x) is a linear function, then:

g(x) = mx + c

For: g(0) = 1

g(x) = mx + c

g(0) = m*0 + c

1 = 0 + c

1 = c

c = 1

For: g(1) = 5

g(x) = mx + c

g(1) = m * 1 + c

5 = m * 1 + c

5 = m + c

Substitute c = 1

5 = m + 1

m = 5 - 1

m =4

So, the function is:

g(x) = mx + c

g(x) = 4x + 1

Calculate g(3)

g(3) = 4*3 + 1

g(3) = 12 + 1

g(3) = 13

3 0
3 years ago
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Alex17521 [72]
3.8 is the answer you already figured it out
8 0
3 years ago
How many movies, m, can she download for $50?
TiliK225 [7]
How much does it cost for one movie
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3 years ago
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4 0
3 years ago
7 = -x+3. Consider the line y = Find the equation of the line that is parallel to this line and passes through the point (-5, 6)
artcher [175]

Answer with explanation:

The equation of line is, y= -x +3

→x+y-3=0---------(1)

⇒Equation of line Parallel to Line , ax +by +c=0 is given by, ax + by +K=0.

Equation of Line Parallel to Line 1 is

  x+y+k=0

The Line passes through , (-5,6).

→ -5+6+k=0

→ k+1=0

→k= -1

So, equation of Line Parallel to line 1 is

x+y-1=0

⇒Equation of line Perpendicular  to Line , ax +by +c=0 is given by, bx - a y +K=0.

Equation of Line Perpendicular to Line 1 is

  x-y+k=0

The Line passes through , (-5,6).

→ -5-6+k=0

→ k-11=0

→k= 11

So, equation of Line Parallel to line 1 is

x-y+11=0

4 0
3 years ago
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