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goldenfox [79]
2 years ago
8

A given poll states “54% of fifth graders read at or above the fifth-grade-level.” If there is a stated margin of error of +/- 2

.5%, what is the 95% confidence interval for this statistic?
Mathematics
1 answer:
marta [7]2 years ago
7 0
The z-score fo a 95% confidence interval is 1.96
Confidence interval of a statistic is given by
C.I.= proportion \pm 1.96(2.5) \\ =54 \pm 4.9 = (54-4.9, 54+4.9) = (49.1, 58.9)
Therefore, we are 95% confident that the proportion of fifth graders who read at or above the fifth grade level is between 49.1 and 58.9.
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Hector puts together two tables to make a long table for a class picnic.
lys-0071 [83]

Answer: 14 feet 4 inches

Step-by-step explanation:

Given: The length of the first table = 7 feet 7 inches

The length of the second table = 6 feet 9 inches

The total length of two tables = 7 feet 7 inches + 6 feet 9 inches

= (7+6) feet (7+9) inches

=13 feet 16 inches

Since 1 feet = 12 inches

The total length of two tables = 13 feet+ (12 inches +4 inches)

=13 feet +( 1 feet +4 inches)

= 14 feet 4 inches

Hence, the total length of the two tables =  14 feet 4 inches

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A fish tank has the shape of a rectangular prism. It has a length of 2 1/4 meters, width of 7/8 meters, and a height of 1 1/2 me
ivolga24 [154]

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8 0
3 years ago
At a little known vacation spot taxi fares are a bargain. A 49 mile taxi ride takes 56 minutes and cost $39.20. You want to find
artcher [175]
And 49 mile costs $39.20
So 1 mile costs $0.80
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8 0
2 years ago
What are x and y? 4x-2y=7<br>x+2y=3
suter [353]

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2 years ago
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Consider the function g(x)=5x2−18x+35. find the area under the curve g(x) from x = 0 to x = 13 and then subtract from it the are
Black_prince [1.1K]
We integrate the given equation such that,

    integral of g(x) = (5/3)x³ - 9x² + 35x

Substituting,
   x = 13
    integral of g(x) = (5/3)(13³) - 9(13)² + 35(13) 
                  = 2595.67

and,   x = 0
   integral of g(x) = 0
  
 The area is 2595.67 - 0 = 2595.67

For the second part,
   x = 1
  integral of g(x) = (5/3)(1)³  - 9(1)² + 35(1)  
             = 27.67

Area under the curve between x = 0 and x = 1 is 27.67


The difference between the two areas is,
    2595.67 - 27.67 = 2568.0

Answer: 2568.0 units squared
8 0
2 years ago
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