3 years ago

Helpppp

Mathematics

1 answer:

Morgarella [4.7K]3 years ago

8 0

1. y = c - x
2. y = ( t - 3x ) / 2
3. y = ( 4p ) / 3
4. y = ( 2 - 4s ) / 3s

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Find the exact value of the trigonometric function given that sinU=-7/25 and cosV=-4/5 (Both U and V are in Quadrant III)

Contact [7]

cosU:-

$\\ \rm\longmapsto \sqrt{1-sin^2U}=\sqrt{1-49/625}=24/25$

As U lies in Q3

cosU=-24/25

sinV

$\\ \rm\longmapsto \sqrt{1-cos^2V}=\sqrt{1-16/25}=3/4$

As V lies in Q3

sinV=-3/5

sin(V-U)=sinVcosU-cosVsinU=(-3/5)(-24/25)-(-4/5)(-7/25)=72/125-28/125=72-28/125=44/125
cos(U-V)=cosUcosV+sinUsinV=(-24/25)(-4/5)+(-7/25)(-3/5)=96/125+21/125=117/125

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2 years ago

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LiRa [457]

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3 years ago

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Alona [7]

Answer and Step-by-step explanation:

This problem requires the use of trigonometric functions, specifically the tangent trig function.

$tan(Angle)=\frac{opposite}{adjacent}$

Plug in the values.

$tan(40) = \frac{8000}{x}$

Multiply by x to both sides, then divide by tan(40) to both sides.

$x = \frac{8000}{tan(40)}$

Now, plug this into a calculator and rounded to the nearest whole number (foot).

x = 9534.0287

x = 9534 ft.

The answer is 9534 ft., the last option.

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Multiply by 15 to solve
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weqwewe [10]

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Step-by-step explanation:

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