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ivann1987 [24]
4 years ago
15

Find the dimensions of the rectangle with area 289 square inches that has minimum perimeter, and then find the minimum perimeter

.
Mathematics
1 answer:
nalin [4]4 years ago
4 0
 <span>To minimize the perimeter you should always have a square. 
sqrt(289) = 17 
The dimensions should be 17 X 17 

To see , try starting at length 1, and gradually increase the length. 
The height decreases at a faster rate than the length increases, up until you reach a square. 

Or if you want to use algebra, Say the width is 17-x 
Then the length is 289/(17-x) 

Now, this is bigger than 17+x, as shown here: 
289/(17-x) > 17+x 
289 > 289 - x^2 
which is true. 
so the perimeter would be bigger than 2 * (17- x + 17 + x) = 2 * (2 * 17) = 4 * 17 

Again, the dimensions should be a square. 17 X 17.</span>
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Seattle-Pipes Co. produces pipes to be supplied to a Seattle utility company. The requirement of the utility company is that the
Goshia [24]

Answer:

Step-by-step explanation:

Hello!

The study variable is

X: Pipe length.

It is known that this variable has a normal distribution and that the distribution parameter varies depending on the process used to manufacture the pipes.

Process A: μ= 200cm δ= 0.5cm

Process B: μ=201cm δ= 1cm

Process C: μ=202cm δ= 1.5cm

Pipes with a length of 200cm or more will be accepted by the utility company (X≥200), but pipes with less than 200cm length will be rejected (X<200)

a. Using Process C, you need to calculate the probability that the pipe will be rejected, symbolically:

P(X<200)

Using the distribution data of process C you have to standardize the value:

P(Z<(200-202)/1.5)= P(Z<-1.33)= 0.09176

b. The requirements change, accepting any pipe between 199 and 202, you have to calculate the probabilities of the pipes being between those lengths using the three process:

Process A:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-200)/0.5)) - P(Z≤(199-200)/0.5))

P(Z≤4) - P(Z≤-2) = 1 - 0.02275 = 0.97725

The probability of the pipe being rejected is 0.02275

Process B:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-201)/1)) - P(Z≤(199-201)/1))

P(Z≤1) - P(Z≤-2) = 0.84134 - 0.02275 = 0.81859

The probability of the pipe being rejected is 1-0.81859= 0.18141

Process C:

P(199≤X≤202) = P(X≤202) - P(X≤199)

P(Z≤(202-202)/1.5)) - P(Z≤(199-202)/1.5))

P(Z≤0) - P(Z≤-2) = 0.5 - 0.02275 = 0.47725

The probability of the pipe being rejected is 1-0.47725= 0.52275

The pipes manufactured using process A has fewer chances of being rejected.

c.

Process A costs $140

P(X≥200)= 1 - P(X<200)= 1 - P(Z<0)= 1 - 0.5= 0.5

Process B costs $160

P(X≥200)= 1 - P(X<200)= 1 - P(Z<-1)= 1 - 0.15866= 0.84134

Process C costs $177

P(X≥200)= 1 - P(X<200)= 1 - P(Z<-1.33)= 1 - 0.09176= 0.90824

If they where to make 100 pipes:

Using process A: 100*0.5= 50 pipes will be accepted, so they'll win 50*($200-$140)= $3000

Using process B: 100*0.84134= 84.134≅ 84 pipes will beaccepted, so they'll win 84*($200-$160)= $3360

Using the process C: 100*0.90824= 80.824≅ 90 pipes will be accepted, so they'll win 90*($200-$177)= $2070

As you can see, using process B will maximize the profits.

I hope it helps!

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3 years ago
Select the correct answer.
katen-ka-za [31]

Answer:

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Step-by-step explanation: bc ik

7 0
3 years ago
Help me plz this is due in 5 minutes and I’m have this disorder and it makes me hard to concentrate and think imma go to the the
Alex Ar [27]

Answer:

p= 24

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In a simplier way, 4 times 6

Step-by-step explanation:

5 0
3 years ago
Read 2 more answers
The side lengths of △JKL are 60 cm, 80 cm, and 100 cm.
Alekssandra [29.7K]

Answer:

2nd option

Step-by-step explanation:

using the converse of Pyhagoras' identity

If the square of the longest side is equal to the sum of the squares on the other 2 sides then the triangle is right.

longest side = 100 , then 100² = 10000

60² + 80² = 3600 + 6400 = 10000

then

60² + 80² = 100²

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4 0
2 years ago
The volume of a cylinder is 40 3. Which expression represents the volume of a cone with the same base and height as the
Novosadov [1.4K]

Answer:

V_{cone}=\frac{1}{3} \,40\,\,ft^3

Step-by-step explanation:

I believe you wanted to type that the volume of a cylinder is 40 cubic feet, and try to find what the volume of the same base and height would be in comparison.

Recall that the volume of a cylinder of base B and height H is given by the formula:

V_{cyl}=B * H

Recall as well that the volume of a cone of base B and height H is given by the formula: V{cone}=\frac{1}{3} B*H

Therefore, if the cone has the same base (B) as the cylinder, and equal height (H), then we can say that the volume of the cone is "one third" of the volume of the cylinder, which in Math terms is written as:

V_{cone}=\frac{1}{3} \,V_{cyl}

Therefore, in our case, given that the volume of the cylinder is 40 ft^3  , the volume of the cone would be:

V_{cone}=\frac{1}{3} \,40\,\,ft^3

8 0
3 years ago
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