Question

A ball is thrown downward from a cliff. Its position at time t seconds is given by the formula s(t) = 16t2 + 32t, where s is in feet. How many seconds (to the nearest tenth) will it take for the ball to fall 215 ft.? Round to the nearest tenth, if necessary.

Answer 1

Answer:

It takes 2.8 seconds for the ball to fall 215 ft.

Step-by-step explanation:

We are given a position function s(t) where s stands for the number of feet the ball has fallen, so we have to replace s with the given value of 215 ft and solve for the time t.

Setting up the equation.

The motion equation is given by

$s(t) =16t^2+32t$

We can replace there s = 215 ft to get

$215=16t^2+32t$

Solving for the time t.

From the previous equation we can move all terms in one side to get

$16t^2+32t-215=0$

At this point we can solve for t using quadratic formula.

$t = \cfrac{-b\pm \sqrt{b^2-4ac}}{2a}$

where a, b and c are the coefficients of the quadratic equation

$at^2+bt+c=0$

So we get

$a=16\\b=32\\c=-215$

Replacing on the quadratic formula we get

$t = \cfrac{-32\pm \sqrt{32^2-4(16)(-215)}}{2(16)}$

Using a calculator we get

$t=-4.8 , t = 2.8$

Physically speaking the only result that makes sense is to move forward in time that give us t = 2.8 seconds.

We can conclude that it takes 2.8 seconds for the ball to fall 215 ft.