Answer:
A
Step-by-step explanation:
When X is less than -1, positive parabola.
We have been given the function 
We know that the range is set of y values for which the function is defined. Therefore, we will find the value for x and then observe the restriction is y's values.

Now, we know that logarithm function is not defined for negative values. Hence, the value for y is always greater than zero.
Therefore, the range of the function is given by y>0
B is the correct option.
Answer:
(-6,9,-3)
Step-by-step explanation:
-3x -y +z=6
-3x-y+3z =0
x-3z =3
Multiply the second equation by -1
-1 *(-3x-y+3z) =0*-1
3x +y -3z =0
Add this to the first equation
-3x -y +z=6
3x +y -3z =0
----------------------
0 + 0 + -2z = 6
Divide by -2
-2z/-2 = 6/-2
z = 6/-2
z=-3
Take the third equation to find x
x-3z=3
x-3(-3) = 3
x+9=3
Subtract 9 from each side
x+9-9 =3-9
x=-6
Now we need to find y
3x +y -3z =0
3(-6) +y -3(-3) =0
-18 +y +9=0
-9+y =0
Add 9 to each side
-9+9+y = 0+9
y=9
(-6,9,-3)
Answer:
K1310.4
Step-by-step explanation:
Basic pay per hour = K7.20
Overtime pay during the week per hour = 1 1/2 * K7. 20 = K10.8
Weekends = 2 * K7.20 = K14.4
Basic hours per week = 70 hours
In a fortnight :
Basic hours = 70 * 2 = 140 hours :
Hence, Overtime during the week = (160 - 140) = 20 hours
Weekend hours = (4 +2) = 6 hours
Total earning :
(140 * 7.20) + (20 * 10.8) + (6 * 14.4)
1008 + 216 + 86.4
= K1310.4
Answer:
(0, 1)
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Equality Properties
<u>Algebra I</u>
- Solving systems of equations using substitution/elimination
Step-by-step explanation:
<u>Step 1: Define Systems</u>
y + 5x = 1
5y - x = 5
<u>Step 2: Rewrite Systems</u>
y + 5x = 1
- Subtract 5x on both sides: y = 1 - 5x
<u>Step 3: Redefine Systems</u>
y = 1 - 5x
5y - x = 5
<u>Step 4: Solve for </u><em><u>x</u></em>
<em>Substitution</em>
- Substitution in <em>y</em>: 5(1 - 5x) - x = 5
- Distribute 5: 5 - 25x - x = 5
- Combine like terms: 5 - 26x = 5
- Isolate <em>x</em> term: -26x = 0
- Isolate <em>x</em>: x = 0
<u>Step 5: Solve for </u><em><u>y</u></em>
- Define equation: 5y - x = 5
- Substitute in <em>x</em>: 5y - 0 = 5
- Subtract: 5y = 5
- Isolate <em>y</em>: y = 1