Answer:
24
Step-by-step explanation:
The question is saying, how many three digit numbers can be made from the digits 3, 4, 6, and 7 but there can't be two of the same digit in them. For example 346 fits the requirements, but 776 doesn't, because it has two 7s.
Okay, on to the problem:
We can do one digit at a time.
First digit:
There are 4 digits that we can choose from. (3, 4, 6, and 7)
Second digit:
No matter which digit we chose for the first digit, there is only going to be 3 of them left, because we already chose one, and you can't repeat that same digit. So there are 3 options.
Third digit:
Using the same logic, there are only 2 options left.
We have 4 choices for the first digit, 3 choices for the second, and 2 for the third.
Hence, this is 4 * 3 * 2 = 24 three-digit numbers that can be made.
8 bra cause that’s the answer I got for sure
Answer: 75% 45/60 is .75 witch is 75%
Step-by-step explanation:
Answer:
#3 1/6, 1/6, 1/2, 1/3, 5/6.
#4 3/12, 4/12, 5/12, 8/12, 9/12
Step-by-step explanation:
#3 is numbers out of six (fractions).
#4 is the same thing. You add all of the numbers (4, 3, and 5) to get the total and then you subtract to get the probability.
These are all I know.
