If 82 out of 100 cockroaches are immune to a pesticide after repeated use in an area, how many would be expected to be immune in
2 answers:
Answer:
Hi!
The answer is: 1.804.000 cockroaches are immune.
Step-by-step explanation:
To solve this problem, you can use <em>the rule of three</em>.
100 ----> 2.200.000 cockroaches // If 100% is 2.200.000 cockroaches
82 ----> x cockroaches // then 82% will be immunes.
Now, multiply 82 by 2.200.000 and divide the result by 100:
<u>1.804.000 cockroaches are immune.</u>
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Answer:
7. cos(X) = 3/5 = 0.6
cos(Y) = 4/5 = 0.8
8. cos(X) = 15/17 ≈ 0.8824
cos(Y) = 8/17 ≈ 0.4706
9. cos(X) = 1/2 = 0.5
cos(Y) = (√3)/2 ≈ 0.8660
Step-by-step explanation:
The trigonometric ratio for cosine is given as follows;
7. The adjacent leg length to ∠X = 27
The length of the hypotenuse side of the triangle = 45
∴ cos(X) = 27/45 = 3/5 = 0.6
Cos(X) = 3/5 = 0.6
The adjacent leg length to ∠Y = 36
∴ cos(Y) = 36/45 = 4/5 = 0.8
cos(Y) = 4/5 = 0.8
8. The adjacent leg length to ∠X = 15
The length of the hypotenuse side of the triangle = 17
∴ cos(X) = 15/17 ≈ 0.8824
The adjacent leg length to ∠Y = 8
∴ cos(Y) = 8/17 ≈ 0.4706
9. The adjacent leg length to ∠X = 13
The length of the hypotenuse side of the triangle = 26
∴ cos(X) = 13/26 = 1/2 = 0.5
Cos(X) = 1/2 = 0.5
The adjacent leg length to ∠Y = 13·√3
∴ cos(Y) = 13·√3/26 = (√3)/2 ≈ 0.8660
cos(Y) = (√3)/2 ≈ 0.8660.