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STatiana [176]
3 years ago
12

468 divided by 18 what is the answer

Mathematics
2 answers:
Kryger [21]3 years ago
4 0

Answer

26

Step-by-step explanation:

If you divide it, it is 26 and to check you can do 18x26 and you'll get 468.

Maslowich3 years ago
3 0

Answer:

26

Step-by-step explanation:

<u>Step 1:  Divide</u>

<u />468 / 18

26

Answer:  26

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1 is 69 degrees. 2 is 111 degrees

Step-by-step explanation:

1 is 69 because when a line intersects with 2 paralell lines, 1 and the 69 degree angle are the same degree. we know that the second angle plus 69 degrees is 180, so 180-69 is 111.

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The probability that a person fails to meet CDC Physical Activity Guidelines for both aerobic and muscle-strengthening activity
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Answer:

a) the probability that a randomly selected person fails to meet the activity guidelines or eats a poor diet is 0.83

b) the probability that a randomly selected person is leading a healthy lifestyle is 0.17

c) the probability that they all 4 people eat a poor diet assuming independence is 0.05308

d) the probability that the first one meets the Physical Activity Guidelines and the last two do not is 0.1364

Step-by-step explanation:

Given the data in the question;

Let E represent the events

E1 = P( person fails to meet CDC Physical Activity Guidelines ) = 0.77

E2 = P( person eats a poor diet ) = 0.48

E3 = P(E1 ∩ E2) = P( both ) = 42

a) What is the probability that a randomly selected person fails to meet the activity guidelines or eats a poor diet?

the probability that a person eats a poor diet or fails to meet the activity guidelines will be;

P( E1 ∪ E2 ) = P(E1) + P(E2) - P(E1 ∩ E2)

so we substitute

P( E1 ∪ E2 ) = 0.77 + 0.48 - 0.42 = 0.83

Therefore, the probability that a randomly selected person fails to meet the activity guidelines or eats a poor diet is 0.83

b) Find the probability that a randomly selected person is leading a healthy lifestyle. That is, they meet the Physical Activity Guidelines and eat a diet that is not poor?

In the light of De-Morgan’s Laws

P( E_1^c ∩ E_2^c ) = 1 - P( E1 ∪ E2 )

so

P( E_1^c ∩ E_2^c ) = 1 - 0.83 = 0.17

Therefore, the probability that a randomly selected person is leading a healthy lifestyle is 0.17

c)  If you randomly select 4 people, what is the probability that they all eat a poor diet assuming independence?

if we select 4 people;

E2 = P( person eats a poor diet ) = 0.48

so

P = ( 0.48 )⁴ = 0.05308

Therefore, the probability that they all 4 people eat a poor diet assuming independence is 0.05308

d)  If you randomly select 3 people, what is the probability that the first one meets the Physical Activity Guidelines and the last two do not?

we select 3 people;

P( person fails to meet CDC Physical Activity Guidelines ) = 0.77

P( person meet CDC Physical Activity Guidelines ) = 1 - 0.77 = 0.23

so

P = 0.23 × ( 0.77)²

P = 0.1364

Therefore, the probability that the first one meets the Physical Activity Guidelines and the last two do not is 0.1364

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