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seraphim [82]
3 years ago
10

(6x² + 36x² + 12) ÷ (x+6)

Mathematics
1 answer:
astra-53 [7]3 years ago
8 0

Answer:

=42x2+1

Step-by-step explanation:

6x2+36x2+12x+6

=42x2+1

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P =$3000, r = 28% , t = 5 years
<span>A = 3000.e^(0.28)(5) = 3000.(4.0551) = $12,165.60</span>
5 0
3 years ago
shira was riding the screamer when it broke down. her seat was 53 jorizontal feet from the central support pole. What was her se
ki77a [65]

Answer:

The possible solutions are 58 degree, 122 degrees, 302 degrees and 238 degrees

Step-by-step explanation:

Please see the attachment

From the figure, it is evident that

cos AOB = OB/OA = 53/100 = 0.53

Thus, cos-1 (0.53) = 58 degrees

AOB = 58 degree

Also, there are can be other values depending on the quadrants

COB = 180 -58 = 122 degrees

FOB = 360 -58 = 302 degrees

EOB = 180 + 58 = 238 degrees

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3 years ago
A baseball player throws a ball from second base to home plate. How far does the player throw the ball? Include a diagram showin
12345 [234]
84.85 feet
Explanation:
7 0
3 years ago
Read 2 more answers
The equation of a parabola is given.y=1/8x^2+4x+20 What are the coordinates of the focus of the parabola?
Lena [83]
He equation of a parabola is x = -4(y-1)^2. What is the equation of the directrix? 
<span>You may write the equation as </span>
<span>(y-1)^2 = (1) (x+4) </span>
<span>(y-k)^2 = 4p(x-h), where (h,k) is the vertex </span>
<span>4p=1 </span>
<span>p=1/4 </span>
<span>k=1 </span>
<span>h=-4 </span>

<span>The directrix is a vertical line x= h-p </span>
<span>x = -4-1/4 </span>
<span>x=-17/4 </span>

<span>------------------------------- </span>
<span>What is the focal length of the parabola with equation y - 4 = 1/8x^2 </span>
<span>(x-0)^2 = 8(y-4) </span>
<span>The vertex is (0,4) </span>
<span>4p=8 </span>
<span>p=2 (focal length) -- distance between vertex and the focus </span>
<span>------------------------------- </span>
<span>(y-0)^2 = (4/3) (x-7) </span>
<span>vertex = (7,0) </span>
<span>4p=4/3 </span>
<span>p=1/3 </span>
<span>focus : (h+p,k) </span>
<span>(7+1/3, 0)</span>
8 0
3 years ago
Read 2 more answers
Select the curve generated by the parametric equations. Indicate with an arrow the direction in which the curve is traced as t i
bixtya [17]

Answer:

length of the curve = 8

Step-by-step explanation:

Given parametric equations are x = t + sin(t) and y = cos(t) and given interval is

−π ≤ t ≤ π

Given data the arrow the direction in which the curve is traces means

the length of the curve of the given parametric equations.

The formula of length of the curve is

\int\limits^a_b {\sqrt{\frac{(dx}{dt}) ^{2}+(\frac{dy}{dt}) ^2 } } \, dx

Given limits values are −π ≤ t ≤ π

x = t + sin(t) ...….. (1)

y = cos(t).......(2)

differentiating equation (1)  with respective to 'x'

\frac{dx}{dt} = 1+cost

differentiating equation (2)  with respective to 'y'

\frac{dy}{dt} = -sint

The length of curve is

\int\limits^\pi_\pi  {\sqrt{(1+cost)^{2}+(-sint)^2 } } \, dt

\int\limits^\pi_\pi  \,   {\sqrt{(1+cost)^{2}+2cost+(sint)^2 } } \, dt

on simplification , we get

here using sin^2(t) +cos^2(t) =1 and after simplification , we get

\int\limits^\pi_\pi  \,   {\sqrt{(2+2cost } } \, dt

\sqrt{2} \int\limits^\pi_\pi  \,   {\sqrt{(1+1cost } } \, dt

again using formula, 1+cost = 2cos^2(t/2)

\sqrt{2} \int\limits^\pi _\pi  {\sqrt{2cos^2\frac{t}{2} } } \, dt

Taking common \sqrt{2} we get ,

\sqrt{2}\sqrt{2}  \int\limits^\pi _\pi ( {\sqrt{cos^2\frac{t}{2} } } \, dt

2(\int\limits^\pi _\pi  {cos\frac{t}{2} } \, dt

2(\frac{sin(\frac{t}{2} }{\frac{t}{2} } )^{\pi } _{-\pi }

length of curve = 4(sin(\frac{\pi }{2} )- sin(\frac{-\pi }{2} ))

length of the curve is = 4(1+1) = 8

<u>conclusion</u>:-

The arrow of the direction or the length of curve = 8

7 0
3 years ago
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