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Keith_Richards [23]
3 years ago
8

In a basketball game, a regular basket was worth 2 points and a long-distance basket was worth 3 points. If there were 45 basket

s in a game and 96 points total, how many regular baskets r and long-distance baskets l were made?
A. r + l = 96; 2r + 3l = 45
66 regular; 30 long-distance
B. r + l = 45; 2r + 3l = 96
39 regular; 6 long-distance
C. r + l = 96; 3r + 2l = 45
33 regular; 12 long-distance
D. r + l = 45; 3r + 2l = 96
37 regular; 8 long-distance
Mathematics
1 answer:
-BARSIC- [3]3 years ago
4 0

Answer:

B. r + l = 45; 2r + 3l = 96

39 regular; 6 long-distance

Step-by-step explanation:

There were 45 baskets, so

(1) r + l = 45

There were 96 points in the game, so

(2) 2r + 3l = 96

Solve equation (1) for l

                    l = 45 – r     Substitute the value for l in Equation (2)

2r + 3(45 – r) = 96      Remove parentheses

 2r + 135 - 3r = 96      Combine like terms

         -r + 135 = 96      Subtract 135 from each side

                  -r = -39      Multiply each side by -1

                  r = 39      Substitute the value of r in Equation (1)

           39 + l = 45        Subtract 39 from each side

                   l = 6

===============

Check:

(1) 39 + 6 = 45

         45 = 45

(2) 2×39 + 3×6 = 96

           78 + 18 = 96

                   96 = 96


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8 0
3 years ago
Prove that for any natural n the number 3^(n+4)−3^n is divisible by 16.
gtnhenbr [62]

Answer:

Proved (See Explanation)

Step-by-step explanation:

Show that 3ⁿ⁺⁴ - 3ⁿ is divisible by 16.

This is done as follows

\frac{3^{n+4} - 3^n}{16}

From laws of indices;

aᵐ⁺ⁿ = aᵐ * aⁿ.

So, 3ⁿ⁺⁴ can be written as 3ⁿ * 3⁴.

\frac{3^{n+4} - 3^n}{16} becomes

\frac{3^n * 3^4 - 3^n}{16}

Factorize

\frac{3^n(3^4 - 1)}{16}

\frac{3^n(81 - 1)}{16}

\frac{3^n(80)}{16}

3ⁿ * 5

5(3ⁿ)

<em>The expression can not be further simplified.</em>

<em>However, we can conclude that when 3ⁿ⁺⁴ - 3ⁿ is divisible by 16, because 5(3ⁿ) is a natural whole number as long as n is a natural whole number.</em>

3 0
3 years ago
Can you guys answer this ?​
nika2105 [10]

Answer:

-7

...................

7 0
3 years ago
Read 2 more answers
I dont get it plzzz help me
cricket20 [7]

Given Equation: \frac{1}{3}h-4(\frac{2}{3}h-3)=\frac{2}{3}h-6

Let us remove parenthesis first.

In order to remove parenthesis, we need to distribute -4 over parenthesis (2/3 h -3).

Distributing -4 over (2/3 h -3), we get,

-4*2/3 h - 4*-3 = -8/3 h + 12.

Substituting this value in original equation, we get

\frac{1}{3}h-\frac{8}{3}h+12 =\frac{2}{3}h-6

Now, in order to make the equation easy to solve, we always remove fractions. In order to remove fraction, we need to find the lowest common denominator of all terms(lcd).

The fraction terms has 3 in denominators, so we could multiply each and every term by 3 to remove 3's from denominators.

Multiplying each equation by 3, we get,

3*\frac{1}{3}h-3*\frac{8}{3}h+3*12 =3*\frac{2}{3}h-3*6

On simplfying this step, we get

1h -8h+36=2h-18

Combining like terms on left side, we get

-7h +36 = 2h -18.

Subtracting 36 from both sides, we get

-7h +36 -36= 2h -18-36.

-7h=2h-54

Subtracting 2h from both sides, we get

-7h-2h=2h-54-2h

-9h = -54

Dividing both sides by -9.

-9h/-9 = -54/-9

h = 6.

Therefore, final answer is h=6.


5 0
3 years ago
Witch algebraic expression has a term with a coefficient of 3
KonstantinChe [14]

Answer:

3x

Step-by-step explanation:

coefficient is the number before the variable

6 0
3 years ago
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