She will have negative eight dollars. Thats all I can say
<span>Let p, np be the roots of the given QE.So p+np = -b/a, and np^2 = c/aOr (n+1)p = -b/a or p = -b/a(n+1)So n[-b/a(n+1)]2 = c/aor nb2/a(n+1)2 = cor nb2 = ac(n+1)2
Which will give can^2 + (2ac-b^2)n + ac = 0, which is the required condition.</span>
Answer:
6 x 2 1/2 + 4 ??? I hope this is correct :)
Step-by-step explanation:
If its not.. I'm so sorry:(
Have a nice day! <3
