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3 years ago

Additive Inverse Property 0 = 5c + what is the missing number?

Mathematics

2 answers:

Vilka [71]3 years ago

7 0

Answer:

Hi there!

Your answer is:

-5c

The full equation is:

0= 5c + (-5c)

Step-by-step explanation:

The additive inverse is whatever two numbers, when added, equal 0. We have a positive 5c here. To get rid of 5c, we must subtract 5c from 5c

I hope this helps!

AysviL [449]3 years ago

4 0

Answer:

(-5c)

Explained,

0 = 5c + (-5c)

0 = 5c - 5c

= 0

I hope you know this

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Hitman42 [59]

Answer:

a) $\bar X= 19.2$ represent the sample mean. And that represent the best estimator for the population mean since $\hat \mu =\bar X=19.2$ b) The 90% confidence interval is given by (17.3;21.1)

c) No, because 18 is above the lower limit of the confidence interval.

d) Because the parent population is assumed to be normally distributed.

The reason of this is because the t distribution is an special case of the normal distribution when the degrees of freedom increase.

Step-by-step explanation:

1) Notation and definitions

n=17 represent the sample size

Part a

$\bar X= 19.2$ represent the sample mean. And that represent the best estimator for the population mean since $\hat \mu =\bar X=19.2$ Part b

$s=4.4$ represent the sample standard deviation

m represent the margin of error

Confidence =90% or 0.90

A confidence interval is "a range of values that’s likely to include a population value with a certain degree of confidence. It is often expressed a % whereby a population means lies between an upper and lower interval".

The margin of error is the range of values below and above the sample statistic in a confidence interval.

Normal distribution, is a "probability distribution that is symmetric about the mean, showing that data near the mean are more frequent in occurrence than data far from the mean".

2) Calculate the critical value tc

In order to find the critical value is important to mention that we don't know about the population standard deviation, so on this case we need to use the t distribution. Since our interval is at 90% of confidence, our significance level would be given by $\alpha=1-0.90=0.1$ and $\alpha/2 =0.05$ . The degrees of freedom are given by: