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jenyasd209 [6]
4 years ago
5

How long would the string be in meters if it is 120 centimeters

Mathematics
1 answer:
nexus9112 [7]4 years ago
4 0
1 meter = 100 centimeters, so 120 centimeters equal to 1.2 meters.
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Pleas ehelp me with math aa
Andrej [43]

Answer:

D.

Step-by-step explanation:

If the triangle has one angle that is equal to 90 then it is a right triangle.

6 0
3 years ago
Read 2 more answers
⎩
kifflom [539]

Answer:

the explicit formula for h(n) is, -65-10n

Step-by-step explanation:

Given that:

h(1) = -75

h(n) = h(n-1)-10              ......[1]

Put n =2 in [1] we have;

h(2) = h(1)-10 = -75-10 = -85

Similarly for n = 3

h(3) = h(3)-10 = -85-10 = -95 and so on...

The series we get;

-75, -85, -95, ....

This is an arithmetic sequence series with common difference(d) = -10

Since,

-85-(-75) = -85+75 = -10,

-95-(-85) = -95+85 = -10 and so on

First term(a) = -75

the Explicit formula for arithmetic sequence is given by:

a_n = a+(n-1)d

where a is the first term,

d is the common difference and

n is the number of terms.

We have to find the explicit formula for h(n);

h(n) = a+(n-1)d

Substitute the given values we have;

h(n) = -75+(n-1)(-10)

or

h(n) = -75-10n+10 = -65-10n

Therefore, the explicit formula for h(n) is, -65-10n


5 0
3 years ago
Read 2 more answers
Solve each equation. 8x^2-24=3x^2-9
Sauron [17]

8 {x}^{2}  - 24 = 3 {x}^{2}  - 9
5 {x}^{2}  = 15
{x}^{2}  = 3
x equals about 1.732 or
\sqrt{3}
5 0
4 years ago
W usng a calculator, paper and pencil, or mental math.
Paraphin [41]

Answer:

Mandy will take 67.5 mins to complete the 15 km race.

Step-by-step explanation:

Given:

Mandy runs 4 km in 18 min

She plans to run in a 15 km race.

We need to find how much time required to run 15 km.

4 km =18 min

15 km = time required for 15 km race

By Using Unitary method we get,

Time required for 15 km = \frac{18\times 15}{4}=67.5 mins

Hence time required by Mandy to complete 15 km race is 67.5 mins.

4 0
4 years ago
Help, pls!!!
alina1380 [7]

Answer:

Step-by-step explanation:

Let's start with this.  When do you think the mean would NOT be an appropriate measure of center?  Well, maybe your  data points are 1,2,4,1,5,3, 1,000,000.  If you took the mean of that it wouldn't be anywhere near any of the numbers, and would just be in between two.  So not in the center at all.  

The point is you want your data set well balanced.  You want about an equal number on one side as the other.  So let's look at yours.  

The furthest away from the middle has 11 on the left side and 12 on the right.  If youw ere weighing them on a scale and took the 11 and 12 as the weight, they would be pretty close to equal.  The next two are 21 and 23.  Less close, but still only two away.  The middle is the middle, so nothing to balance it out with.  If you look at it as a whole, the right side is 3 more than the left.  I would say 3 is still pretty close when you are looking at "weights" above 10.  So I would say mean is a pretty appropriate measure of center.  

Stats takes a lot of "gut feelings" like this.  Thinking, "yeah, these are pretty close" so you'll get the hang of it pretty soon.  

6 0
4 years ago
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