No; a range value has two domain values.
f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Step-by-step explanation:
interchanging the variables
x = 5y^2 + 10
5y^2 +10 = x
5y^2 = x - 10
dividing by 5
5y^2/5 = x/5 + -10/5
y^2 = x/5 + - 10/5
y^2 = x/5 - 2
y = 5 (x-10) 0/5 (sq.rt)
g(5x^2 + 10) = 5x/5
g(5x^2 + 10) = x
f^-1(x) = sq.rt 5(x - 10)/5, sq.rt 5(x - 10)/5 is the inverse of y = 5x^2 +10
Answer:
the slope would be -5
Step-by-step explanation:
in linear equations, the slope of the line is the coefficient of x
so in this case, it is -5
Answer:
0.643
Step-by-step explanation:
Let, s = play a sport
c = participate in a club
P(s) = 0.14
P(s n c) = 0.09
probability that a student participates in
a club given that they also play a sport = P(c | s)
P(c | s) = P(c n s) / P(s)
P(c | s) = 0.09 / 0.14
P(c | s) = 0.64285
= 0.643