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german
4 years ago
11

Graph the relation. Is the relation a function? Why or why not? {(–5, 6), (–2, 3), (3, 2), (6, 4)} No; a domain value has two ra

nge values. Yes; there is only one range value for each domain value. No; a range value has two domain values. Yes; there is only one domain value for each range value.

Mathematics
2 answers:
RoseWind [281]4 years ago
4 0

Answer:

Yes; there is only one range value for each domain value

Step-by-step explanation:

A relation can be defined as a function f(x) if for each value of the domain of x, there exists a unique value of f(x).

For example

(2, 4)(3, 9)(-2, 4)(4, 16) Is a Function

(2, 4)(2,6)(3, 8)(3, -8) Is Not a Function

To analyze if the relationship shown is a function, you must observe that each value of the domain has a single value of the range assigned.

For the given points {(-5, 6), (-2, 3), (3, 2), (6, 4)} this requirement is satisfied. Therefore, the relationship is a function. The graph is shown in the attached image.

The correct option is: Yes; there is only one range value for each domain value

balandron [24]4 years ago
3 0

Answer:

Yes; there is only one range value for each domain value.

Step-by-step explanation:

Let, R = {(-5, 6), (-2, 3), (3, 2), (6, 4)} is a relation,

Since, a relation is called a function if there is only one output value for each input value,

Here, the image of -5 is 6,

Image of -2 is 3,

Image of 3 is 2,

Image of 6 is 4,

That is, there is only one output value for each distinct input value,

Thus, R is a function,

Now, the input value is called domain value and output value is called range value,

Hence, SECOND OPTION is correct.

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Brown rice costs $2 per pound, and beans cost $1.60 per pound. Lin has $10 to spend on these items to make a large meal of beans
Valentin [98]

Answer:

1.   2r+1.6b=10

2.  r=5-0.8b

3.  b=6.25-1.25r

Step-by-step explanation:

<h3> The complete exercise is: "Brown rice costs $2 per pound, and beans cost $1.60 per pound. Lin has $10 to spend on these items to make a large meal of beans and rice for a potluck dinner. Let b be the number of pounds of beans Lin buys and r be the number of pounds of rice she buys when she spends all her money on this meal.</h3><h3>1. Write an equation relating the two variables.</h3><h3>2. Rearrange the equation so "b" is the independent variable.</h3><h3>3. Rearrange the equation so "r" is the independent variable."</h3><h3 />

1. According to the information exercise given in the exercise, the cost per pounds of brown rice is $2. Since "r" represents the number of pounds of rice Lin buys, the total cost of the brown rice she buys can be represented with this expression:

2r

The beans cost $1.60 per pound. Since "b" represents the number of pounds of beans Lin buys, the total cost of beans she buys can be represented as:

1.6b

Knowing that she spends $10, you can write the following equation:

2r+1.6b=10

2. In order to rearrange the equation so "b" is the independent variable, you need to solve for "r":

2r+1.6b=10\\\\2r=10-1.6b\\\\r=\frac{10-1.6b}{2} \\\\r=5-0.8b

3. To rearrange the equation so "r" is the independent variable, you must solve for "b". You get:

2r+1.6b=10\\\\1.6b=10-2r\\\\b=\frac{10-2r}{1.6}\\\\b=6.25-1.25r

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