Cyber savvy is the technologically knowledgeable person who knows about the computers and internet. They can overcome apathy by connecting to a large population.
<h3>What is cyber-savvy?</h3>
Cyber savvy is the protection against data theft from online platforms and having immense knowledge about the internet. It can be used to reach a mass number of people in cases of human rights violations.
Human rights are the civil rights that work in gruesome cases that violate the basic human rights and fundamentals. The cases of human rights can be solved by campaigns that aware people of cybercrimes and threats.
Therefore, the cyber-savvy can launch campaigns to deal with the human rights violation acts.
Learn more about cyber savvy here:
brainly.com/question/27430379
#SPJ1
For this we will use kinematic equations.
We need the time of flight to compute the range.
With the given information, the most useful formula is:
Δy=v0yt−g2t2
Because our equation is taking only vertical motion into account,
v0y=30sin(45)
Because we are looking for the range of the object,
Δy=0
This leaves us with only one unknown: t
0=30sin(45)t−g2t2
g2t2=30sin(45)t
g2t=30sin(45)
t=60gsin(45)
For horizontal distance, the formula we need is:
Δx=v0xt
Because we are taking into account the horizontal range,
v0x=30cos(45)
In substituting our derived values into the equation we can see that:
Δx=30cos(45)∗60gsin(45)
Range=30cos(45)∗60gsin(45)
Krypton (Kr) and bromine (Br) are Period 4 elements that are also called p-block elements. Krypton is a noble gas while bromine is a halogen.
While comparing the stability of the two elements, Krypton is more stable than bromine. This is because being a noble gas, Krypton follows the octet rule and maintains its stability. Bromine has 35 electrons and the outer most valence shell has 7 electrons so its unstable. Krypton has 36 electrons and 8 electrons in the valence shell so its stable.
Answer:
I put 7 but im not sure if it correct yet
Explanation:
if point U is on RS but the U to P is 7 units then U must be the midpoint of RS but i have no idea hope this helps