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Sophie [7]
3 years ago
13

Please help with #12

Mathematics
1 answer:
ExtremeBDS [4]3 years ago
8 0

Answer:

a. 1 1/8 b. 8/9

Step-by-step explanation:

You can set this up as a proportion to solve.  For part a. we know that 2/3 of the road is 3/4 mile long.  2/3 + 1/3 = the whole road, so we need how many miles of the road is 1/3 its length.  Set up the proportion like this:

\frac{\frac{2}{3} }{\frac{3}{4} } =\frac{\frac{1}{3} }{x}

Cross multiplying gives you:

\frac{2}{3}x=\frac{1}{3}*\frac{3}{4}

The 3's on the right cancel out nicely, leaving you with

\frac{2}{3}x=\frac{1}{4}

To solve for x, multiply both sides by 3/2:

\frac{3}{2}*\frac{2}{3}x=\frac{1}{4}*\frac{3}{2} gives you

x=\frac{3}{8}

That means that the road is still missing 3/8 of a mile til it's finished.  The length of the road is found by adding the 3/4 to the 3/8:

\frac{3}{4}+\frac{3}{8}=\frac{6}{8}+\frac{3}{8}=\frac{9}{8}

So the road is a total of 1 1/8 miles long.

For b. we need to find out how much of 1 1/8 is 1 mile:

1 mile = x * 9/8 and

x = 8/9.  When 1 mile of the road is completed, that is 8/9 of the total length of the road completed.

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\frac{x - 1}{3(x+ 1)}

VII)

\frac{2(m - 7) \times (m + 7)}{n(n - 7)}

Step-by-step explanation:

VI)

\frac{{(x + 1)}^{2}}{6}  \times  \frac{2}{{x}^{2} - 1}

= \frac{2{(x - 1)}^{2} }{6(x - 1) \times (x + 1)}

=  \frac{x - 1}{3(x+ 1)}

VII)

\frac{{m}^{2}  - 49}{3n}  \div  \frac{2n - 14}{6}

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6 0
3 years ago
Divide:(10x²-3x+4)÷(2x-5)
Helen [10]

Answer:

\frac{10x^2-3x+4}{2x-5}=5x+11+\frac{59}{2x-5}

Quotient: 5x+11

Remainder: 59

Step-by-step explanation:

I'm going to do long division.

The bottom goes on the outside and the top goes in the inside.

  Setup:

        ---------------------------------

2x-5 |  10x^2    -3x      +4

  Starting the problem from the setup:

            5x     +11                        (I put 5x on top because 5x(2x)=10x^2)

        ---------------------------------   (We are going to distribute 5x to the divisor)

2x-5 |  10x^2    -3x      +4

        -(10x^2  -25x)                  (We are now going to subtract to see what's left.)

      -----------------------------------

                      22x      +4          (I know 2x goes into 22x, 11 times.)

                                                ( I have put +11 on top as a result.)

                    -(22x     -55)        (I distribute 11 to the divisor.)

                 -----------------------

                                  59          (We are done since the divisor is higher degree.)

The quotient is 5x+11.

The remainder is 59.

The result of the division is equal to:

5x+11+\frac{59}{2x-5}.

We can actually use synthetic division as well since the denominator is linear.

Let's solve 2x-5=0 to find what to put on the outside of the synthetic division setup:

2x-5=0

Add 5 on both:

2x=5

Divide both sides by 2:

x=5/2

Or realize that 2x-5 is the same as 2(x-(5/2)) which you will have to do anyways if you choose this route:

So 5/2 will go on the outside:

5/2  |    10          -3            4

      |                  25         55

         ------------------------------

           10          22        59

So we have:

\frac{10x^2-3x+4}{2x-5}

=\frac{10x^2-3x+4}{2(x-\frac{5}{2})}=\frac{1}{2} \cdot \frac{10x^2-3x+4}{x-\frac{5}{2}}=\frac{1}{2}(10x+22+\frac{59}{x-\frac{5}{2}})

Distribute the 1/2 back:

\frac{10x^2-3x+4}{2x-5}=\frac{10x+22}{2}+\frac{59}{2(x-\frac{5}{2})}

\frac{10x^2-3x+4}{2x-5}=5x+11+\frac{59}{2x-5}

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Step-by-step explanation:

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